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2 years ago

Where does the peak intensity need to fall on the spectrum for a very intense star?

Chemistry

2 answers:

umka2103 [35]2 years ago

8 0

Answer: A

Explanation: I got it right on my test

Brainliest?

viva [34]2 years ago

7 0

Answer:

Gamma range

Explanation:

A very intense start is a bright star at very high temperature. Now, hotter the object shorter is the wavelength of peak radiation. The increasing order of wavelength of the given regions in the electromagnetic spectrum are:

gamma range < ultra violet < visible < infrared

Ideally, since the shortest wavelength based on the given options is the gamma range, the peak intensity can also be expected to fall at that wavelength. If the star spectrum was recorded in the UV-visible range of the EM spectrum, then it would fall in the UV range

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Why are caves usually found in limestone-rich regions?

aliya0001 [1]

Cause limestone breaks down dirt and stone

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2 years ago

Help asap on a time crunch

marusya05 [52]

Answer:

only sodium chloride compounds MOST LIKELY products of the reaction between sodium metal and chlorine gas.

Correct answer - C

Explanation:

A solid sodium metal reacts with gaseous form of chlorine gas to form a solid sodium chloride.

This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.

As a result, an ionic compound solid sodium chloride is formed.

The chemical reaction of formation sodium chloride is as follows.

$2Na(s)+Cl_{2}(g) \rightarrow 2NaCl(s)$

Therefore, only sodium chloride compounds MOST LIKELY products of the reaction between sodium metal and chlorine gas.

7 0

3 years ago

Hellllppppp lons Worksheet

Iteru [2.4K]

The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

Element--valence electron--electrons to gain--electrons to lose--ion formed

O ------------ 6 ---------------------- 2 ------------------------ none -------------- $O^{2-}$

Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ $Ca^{2+}$

Br ----------- 7 --------------------- 1 ------------------------ none --------------- $Br^{-}$

S ------------ 6 ----------------------- 2 ------------------------ none --------------- $S^{2-}$

Cl ------------ 7 ----------------------- 1 ------------------------ none ---------------- $Cl^{-}$

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ $K^{+}$

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- $Mg^{2+}$

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- $Be^{2+}$

Learn more here: brainly.com/question/21089350

8 0

2 years ago

Which equation represents the oxidation half-reaction for this redox reaction? Ca + Al(NO3)3 → Al + Ca(NO3)2

vodomira [7]

The oxidation half reaction of the reaction given above would be: Ca → Ca + 2e−. Oxidation is the loss of electrons of an element while its counterpart is called the reduction which gains the electrons that has been lost. Hope this answers the question.

5 0

2 years ago

Read 2 more answers

What orbital is represented by the transition metals in period four

andreev551 [17]

The name transition metal refers to the position in the periodic table of elements. The transition elements represent the successive addition of electrons to the d atomic orbitals of the atoms. In this way, the transition metals represent the transition between group 2 (2A) elements and group 13 (3A) elements.

8 0

3 years ago