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dezoksy [38]
3 years ago
13

Where does the peak intensity need to fall on the spectrum for a very intense star?

Chemistry
2 answers:
umka2103 [35]3 years ago
8 0

Answer: A

Explanation:  I got it right on my test

Brainliest?

viva [34]3 years ago
7 0

Answer:

Gamma range

Explanation:

A very intense start is a bright star at very high temperature. Now, hotter the object shorter is the wavelength of peak radiation. The increasing order of wavelength of the given regions in the electromagnetic spectrum are:

gamma range < ultra violet < visible < infrared

Ideally, since the shortest wavelength based on the given options is the gamma range, the peak intensity can also be expected to fall at that wavelength. If the star spectrum was recorded in the UV-visible range of the EM spectrum, then it would fall in the UV range

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5. If 1 g of a gas occupies a volume of 300 mL at STP, what is the molecular weight of the gas?
ikadub [295]

Answer:

74,67 gr/mol

Explanation:

At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)

n=0,3L/22,4 L=0,01339 mol

Since we know weight of the gas as 1 g, we can find the molecular weight as;

MW=1 g/0,01339 mol =74,67 gr/mol

3 0
3 years ago
For two variables in a direct proportion, what is the result of doubling one variable?
Airida [17]

Answer:

the other variable is also doubled

Explanation:

direct proportion, same thing has to happen to both variables

6 0
3 years ago
Normal red blood cells slide easily through narrow blood vessels. In sickle cell disease, many red blood cells change to a cresc
dybincka [34]

Answer:

C. The child must have inherited sickle cell genes from both parents.

Explanation:

Because of the fact that sickle cell disease is recessive, the child would have to get the gene from both parents.

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3 years ago
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Which choice is an example of a consumer? Question 9 options: tree fungi bee sun
xz_007 [3.2K]
The correct answer is C) Bee, any living thing, such as a bee, cannot make its own food therefor it is a consumer
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a) Whatis the composition in mole fractions of a solution of benzene and toluene that has a vapor pressure of 35 torr at 20 °C?
iogann1982 [59]

Answer:

molar composition for liquid

xb= 0.24

xt=0.76

molar composition for vapor

yb=0.51

yt=0.49

Explanation:

For an ideal solution we can use the Raoult law.

Raoult law: in an ideal liquid solution, the vapor pressure for every component in the solution (partial pressure) is equal to the vapor pressure of every pure component multiple by its molar fraction.  

For toluene and benzene would be:

P_{B}=x_{B}*P_{B}^{o}

P_{T}=x_{T}*P_{T}^{o}

Where:

P_{B} is partial pressure for benzene in the liquid  

x_{B} is benzene molar fraction in the liquid  

P_{B}^{o} vapor pressure for pure benzene.  

The total pressure in the solution is:

P= P_{T}+ P_{B}

And  

1=x_{B}+x_{T}

Working on the equation for total pressure we have:

P=x_{B}*P_{B}^{o} + x_{T}*P_{T}^{o}

Since x_{T}=1-x_{B}

P=x_{B}*P_{B}^{o} + (1-x_{B})*P_{T}^{o}

We know P and both vapor pressures so we can clear x_{B} from the equation.

x_{B}=\frac{P- P_{T}^{o}}{ P_{B}^{o} - P_{T}^{o}}

x_{B}=\frac{35- 22}{75-22} = 0.24

So  

x_{T}=1-0.24 = 0.76

To get the mole fraction for the vapor we know that in the equilibrium:

P_{B}=y_{B}*P

y_{T}=1-y_{B}

So  

y_{B} =\frac{P_{B}}{P}=\frac{ x_{B}*P_{B}^{o}}{P}

y_{B}=\frac{0.24*75}{35}=0.51

y_{T}=1-0.51=0.49

Something that we can see in these compositions is that the liquid is richer in the less volatile compound (toluene) and the vapor in the more volatile compound (benzene). If we take away this vapor from the solution, the solution is going to reach a new state of equilibrium, where more vapor will be produced. This vapor will have a higher molar fraction of the more volatile compound. If we do this a lot of times, we can get a vapor that is almost pure in the more volatile compound. This is principle used in the fractional distillation.

7 0
3 years ago
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