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3 years ago

Find the GCF of the numbers using lists of factors. 27,45 30,48 28,48,64

Mathematics

1 answer:

Svetach [21]3 years ago

6 0

Answer:

1.) 6

2.)6

3,)4

Step-by-step explanation:

I think these are the gcf of the numbers

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Solve: 2/3x - 3/4 = 5 + 5/6x

Slav-nsk [51]

Answer:

$\large\boxed{x=-\dfrac{69}{2}\to x=-34\dfrac{1}{2}\to x=-34.5}$

Step-by-step explanation:

$\dfrac{2}{3}x-\dfrac{3}{4}=5+\dfrac{5}{6}x\qquad\text{multiply both sides by LCD = 12}\\\\12\!\!\!\!\!\diagup^4\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-12\!\!\!\!\!\diagup^3\cdot\dfrac{3}{4\!\!\!\diagup_1}=(12)(5)+12\!\!\!\!\!\diagup^2\cdot\dfrac{5}{6\!\!\!\diagup_1}x\\\\(4)(2x)-(3)(3)=60+(2)(5x)\\\\8x-9=60+10x\qquad\text{add 9 to both sides}\\\\8x-9+9=60+9+10x\\\\8x=69+10x\qquad\text{subtract}\ 10x\ \text{from both sides}\\\\8x-10x=69+10x-10x\\\\-2x=69\qquad\text{divide both sides by (-2)}\\\\x=-\dfrac{69}{2}$

7 0

4 years ago

Ciro purchased a concert ticket for $56 . The cost of the ticket was 4/5 the cost of his dinner. The cost of his hotel was 2 1/2

NeTakaya

$266

<h3>Further explanation</h3>

<u>Given:</u>

Ciro purchased a concert ticket for $56.

The cost of the ticket was ⁴/₅ the cost of his dinner.

The cost of his hotel was 2¹/₂ times much as his ticket.

<u>Question:</u>

How much did Ciro spend altogether for the concert ticket, hotel, and dinner?

<u>The Process:</u>

Note from all the data above we can start from the cost of his dinner by forming a pattern of 5 units.

$Dinner: \boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}$

Since the cost of the ticket is ⁴/₅ the cost of the dinner, then we arrange the cost of the ticket by forming a pattern of 4 units containing $ 14 each. Recall that $\boxed{\$ 56 \div 4 = \$ 14}$

$Ticket: \boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14} = \$ 56$

Let us calculate the cost of his dinner:

$\boxed{ \ 1 \ unit = \$ 14 \rightarrow 5 \ units = \$ \ ? \ }$

$Dinner: \boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14} = \$ 70}$

$\boxed{ \ \ or \ 5 \ unit \times \$ 14 = \$ 70 \ }$

Hence, the cost of his dinner is $\boxed{\boxed{ \ \$ 70 \ }}$

Since the cost of his hotel is 2¹/₂ times much as his ticket, then we arrange the cost of his hotel by forming a pattern of two and one-half units of the cost of ticket.

Let us calculate the cost of his hotel:

$\boxed{ \ 1 \ ticket = \$ 56 \rightarrow 2\frac{1}{2} \ units = \$ \ ? \ }$

$Hotel: \boxed{\$ 56}\boxed{\$ 56}\boxed{\$ 28} = \$ 140}$

$\boxed{ \ \ or \ \frac{5}{2} \ unit \times \$ 56 = \$ 140 \ }$

Recall that $\boxed{\ 2\frac{1}{2} = \frac{5}{2}}$

Hence, the cost of his hotel is $\boxed{\boxed{ \ \$ 140 \ }}$

In the final step, we calculate how much Ciro spend altogether for the concert ticket, hotel, and dinner.

$\boxed{ \ The \ concert \ ticket = \$ 56 \ }$

$\boxed{ \ The \ hotel = \$ 140 \ }$

$\boxed{ \ The \ dinner = \$ 70 \ }$

$\boxed{ \ \$ 56 + \$ 140 + \$ 70 = \$ 266 \ }$

Thus, Ciro spent $266 altogether for the concert ticket, hotel, and dinner.

<h3>Learn more</h3>

What is the width of the actual snowflake? brainly.com/question/1070912
How much does his cat weigh (Jesse's)? brainly.com/question/388037
How much more paint will Mathilde need to buy? brainly.com/question/36885

Keywords: Ciro purchased a concert ticket for $56, pattern, 4/5 the cost of his dinner, the cost of his hotel was 2 1/2 times much as his ticket, Ciro spend altogether

4 0

4 years ago

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Parker has a bag that contains orange chews, apple chews, and lime chews. He performs an experiment. Parker randomly removes a c

AleksAgata [21]

Answer:

31/40

Step-by-step explanation:

13/40 + 18/40

5 0

3 years ago

Math Help Please....

rodikova [14]

Let's go through the answer choices one by one:

A. False. The line segment contains more than just the endpoints

B. False. There are points in this description that extend beyond the endpoints. If this was a line instead of a segment, then choice B would be the answer

C. True. This is the answer. Though your teacher should have added "collinear" to the sentence to make it clear that the points are between M and N, and also collinear to M and N. All of these points form the line segment MN

D. False. That would be the perpendicular bisector of MN

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So once again, the final answer is choice C

8 0

3 years ago

Select the correct answer.

nika2105 [10]

C. 6

$6 {n}^{2} + 15$

the coefficient is the number in front of the variable (letter)

4 0

3 years ago

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