Answer:
The force that you must exert on the balloon is 1.96 N
Explanation:
Given;
height of water, h = 4.00 cm = 4 x 10⁻² m
effective area, A = 50.0 cm² = 50 x 10⁻⁴ m²
density of water, ρ = 1 x 10³ kg/m³
Gauge pressure of the balloon is calculated as;
P = ρgh
where;
ρ is density of water
g is acceleration due to gravity
h is height of water
P = 1 x 10³ x 9.8 x 4 x 10⁻²
P = 392 N/m²
The force exerted on the balloon is calculated as;
F = PA
where;
P is pressure of the balloon
A is the effective area
F = 392 x 50 x 10⁻⁴
F = 1.96 N
Therefore, the force that you must exert on the balloon is 1.96 N
Answer:
Work done, W = 750 joules
Explanation:
It is given that,
Force acting on the object, F = 50 N
It moves to a distance of, d = 15 meters
We need to find the work done on an object. We know that the product of force and distance covered is called the work done. As the force and the displacement are in same direction. So,
W = 750 joules
So, the work done on an object is 750 joules. Hence, this is the required solution.
Answer:
charge and distance
Explanation:
The electric force between the two particles are calculated using the formular:
F = kQ₁Q₂ / d²
where:
F = force.
k= Coulomb's law constant.
Q1 and Q2 are the charges.
d= distance.
the equation above is called Coulomb's law.
It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.
so the correct option is charge and distance.
