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masha68 [24]
4 years ago
12

If manuel weighs 375 n and is holding the box. how much force is the floor exerting on him? (include direction)

Physics
1 answer:
denis23 [38]4 years ago
4 0
<span> The box is exerting a force of its weight. So we'll use W=mg (Note: you can use the notation F=ma, doesn't matter since weight IS a force.) We can call g negative since it's directed down towards the earth. 
</span>
<span>W = 5kg(-9.8 m/(s^2)) = -49 N 
</span>
<span>Thus, the box exerts a force of 49N downwards. </span>
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A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend
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Answer:

A. Ein = 8.05*10^-4 V/m

B. Clockwise sense

Explanation:

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\int E_{in} \cdot ds=-\frac{d\Phi_B}{dt}            (1)

Ein: induced electric field

ds: differential of a path of the ring

ФB: magnetic flux in the ring

The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):

\int E_{in}ds=E_{in}(2\pi r)=-A\frac{dB}{dt}\\\\E_{in}=-\frac{A}{2\pi r}\frac{dB}{dt}   (2)

dB/dt = -0.280T/s     (it is decreasing)

A: area of the ring = π(r/2)^2= (π/4) r^2

r: radius of the ring = 4.60/2 = 2.30 cm

Then, you replace the values of all variables in the equation (2):

E_{in}=-\frac{(\pi/4)r^2}{2\pi r}\frac{dB}{dt}=\frac{r}{8}\frac{dB}{dt}\\\\E_{in}=-\frac{0.0230m}{8}(-0.280T)=8.05*10^{-4}\frac{V}{m}

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6 0
4 years ago
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Answer:A::C

Solution :

ΔT=

1

2

 

TαΔθ

rArr Δt=

ΔT

T1t

 

But T′≈T

∴Δt=

1

2

 

αΔθ(t)

=

1

2

 

×0.000012×20×24×3600

=10.37s

At higher temperture, length of pendulum clock will be more. So, time period will be more and it will lose the time.

Explanation:

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