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nekit [7.7K]
3 years ago
15

Suppose a scientist doing an experiment in nuclear fusion starts out with twelve atoms. How many atoms will most likely result f

rom the experiment?
Physics
1 answer:
Alisiya [41]3 years ago
7 0
X≤10: The definition of nuclear fusion says: a reaction in whicih 2 OR MORE atoms come close enough together to form one or more different atomic nuclei and subatomic particles.

x=the number of atoms at the end

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How much current is drawn by a television with a resistance of 30 ω that is connected across a potential difference of 120v?
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By using the Ohms law, we can calculate the current.

Ohms law,

 \frac{V}{I}  = R

Here, V is potential difference, and R is the resistance.

Given,  V=120 V and R = 30 ohm.

Therefore, putting the given values in above relation , we get

\frac{120V}{I} = 30 ohm

or          I=\frac{120}{30} = 4 A

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3 years ago
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Assuming that the smallest measurable wavelength in an experiment is 0.950 fm , what is the maximum mass of an object traveling
Arada [10]

Answer:

The maximum mass is 2.89x10^{-21}Kg

Explanation:

The wavelength of the electron can be determined by means of the De Broglie equation.

\lambda = \frac{h}{p} (1)

Where h is the Planck's constant and p is the momentum.

\lambda = \frac{h}{mv}  

m = \frac{h}{\lambda v}  (2)

Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

\lambda = 0.950fm .\frac{1m}{1x10^{15}fm} -- 9.5x10^{-16}m

Finally, equation 2 can be used.

m = \frac{6.624x10^{-34} J.s}{(9.5x10^{-16}m)(241m/s)}

But 1J = Kg.m^{2}/s^{2}

m = \frac{6.624x10^{-34} Kg.m^{2}/s^{2}.s}{(9.5x10^{-16}m)(241m/s)}

m = 2.89x10^{-21}Kg    

Hence, the maximum mass is 2.89x10^{-21}Kg

6 0
3 years ago
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