Answer:
Heat generated in the rod is 8.33 watts.
Explanation:
It is given that,
Length of rod, l = 2 m
Area of cross section, 
Resistivity of rod, 
Potential difference, V = 0.5 V
The value of resistance is given by :
R = 0.03 ohms
Let H is the rate at which heat is generated in the rod . It is given by :
Since, 
So, the at which heat is generated in the rod is 8.33 watts. Hence, this is the required solution.
There is no SI "base unit" of density.
(Any unit of mass) divided by (any unit of volume) is
a valid unit of density.
The units of density that are seen most often are
(gram per cm³) and (kgm per meter³) .
Answer:
The radius of the gold nucleus is 7.1x10⁻¹⁵m
Explanation:
The nearest distance is:
(eq. 1)
Where
z = atomic number of gold = 79
e = electron charge = 1.6x10⁻¹⁹C
k = electrostatic constant = 9x10⁹Nm²C²
energy of the particle = 32 MeV = 5.12x10⁻¹²J
At the potential energy is zero, all the energy will be kinetic energy:
Where
m = 4 mp = mass of proton
Replacing in equation 1
Answer:
mgh₁ + ½mv₁² = mgh₂ + ½mv₂²
Explanation:
Initial total energy = final total energy
PE₁ + KE₁ = PE₂ + KE₂
mgh₁ + ½mv₁² = mgh₂ + ½mv₂²
Answer:
Muatan listrik yang mengalir dari potensial tinggi ke potensial rendah disebut
elektron
Explanation:
semoga ini membantu (:
