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3 years ago

2. Can the frictional force in this experiment be ignored? Explain.

Physics

1 answer:

neonofarm [45]3 years ago

5 0

Answer:

i dont know

Explanation:

i dont know

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An infinitely long line of charge has a linear charge density of 7.50×10^−12 C/m . A proton is at distance 14.5 cm from the line

Nata [24]

Answer:

10.22 cm

Explanation:

linear charge density, λ = 7.5 x 10^-12 C/m

distance from line, r = 14.5 cm = 0.145 m

initial speed, u = 3000 m/s

final speed, v = 0 m/s

charge on proton, q = 1.6 x 10^-19 C

mass of proton, m = 1.67 x 10^-27 kg

Let the closest distance of proton is r'.

The potential due t a line charge at a distance r' is given by

$V=-2K\lambda ln\left (\frac{r'}{r} \right )$

where, K = 9 x 10^9 Nm^2/C^2

W = q V

By use of work energy theorem

Work = change in kinetic energy

$qV = 0.5m(u^{2}-v^{2})$

By substituting the values, we get

$V=\frac{mu^{2}}{2q}$

$-2K\lambda ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{2q}$

$- ln\left ( \frac{r'}{r} \right )=\frac{mu^{2}}{4Kq\lambda }$

$- ln\left ( \frac{r'}{r} \right )=\frac{1.67 \times 10^{-27}\times 3000\times 3000}{4\times 9\times 10^{9}\times 1.6\times 10^{-19}\times 7.5\times 10^{-12} }$

$- ln\left ( \frac{r'}{r} \right )=0.35$

$\frac{r'}{r} =e^{-0.35}$

$\frac{r'}{r} =0.7047$

r' = 14.5 x 0.7047 = 10.22 cm

5 0

4 years ago

Kwanzaa farts apple juice

8_murik_8 [283]

Answer:

well

Explanation:

7 0

3 years ago

A helicopter flying at a distance of 20.0 km from a radio transmitter receives a signal of intensity 35.1 μW/m2.

irinina [24]

Answer:

a) 0.162 V/m

b) 0.54 nT

c) 22 kW

Explanation:

Given

Distance of flight, d = 20 km

Intensity of signal, I = 35.1 μW/m²

Magnitude of the electric component is gotten using the formula

E(m) = √(2Iμc), where

E(m) = √(2 * 35*10^-6 * 4*3.142*10^-7 * 3*10^8)

E(m) = √(2 * 35*10^-6 * 1.257*10^-6 * 3*10^8)

E(m) = √0.0264

E(m) = 0.162 V/m

Magnitude of magnetic component can be gotten by using the relation

B(m) = E(m) / c

B(m) = 0.162 / 3*10^8

B(m) = 5.4*10^-10

B(m) = 0.54 nT

Transmission power, P = IA

where A = 1/2 * 4πr²

P = 2Iπr²

P = 2 * 35*10^-6 * 3.142 * (10000)²

P = 2 * 35*10^-6 * 3.142 * 1*10^8

P = 21994 W

Thus, the transmission power is 22 kW

5 0

3 years ago

1. Consider the position vs time graph at right.

Lemur [1.5K]

Answer:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

Enjoy your long weekend!

Explanation:

Labor Day Weekend--No School

9/1/2021

Hello Students!

There will be no School on Friday Sept 3 and Monday Sept 6

All centers will be closed on Friday 9/3 and Monday 9/6

School will resume on TUESDAY, Sept 7

Enjoy your long weekend!

5 0

3 years ago

What is the period of a wave traveling with a speed of 20 m/s and the wavelength is 4.0 m?

ExtremeBDS [4]

Explanation:

speed= frequency * wavelength

20=x*4

frequency=20/4

=5Hz

period=1/frequency

1/5

=0.2

6 0

2 years ago

Read 2 more answers