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iren2701 [21]
3 years ago
9

What is the Orbital Notation for Radon

Physics
1 answer:
Marina CMI [18]3 years ago
3 0

Answer:

[Rn]7s2

Explanation:

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Summarize: Based on what you have learned, how will the sound that the observer hears
Reil [10]

Answer: The sound will change due to changes in frequency and the wavelength of the airplane.

Explanation: Let assume that the observer is at a stationary position. The wavelength of the sound from the airplane reduces and the frequency increases as the plane is moving toward the observer. As the airplane passes by, that is, moving away from the observer, the frequency starts to reduce while the wavelength of the sound starts to increase.

The sound that the observer hears will change base on the illustration above.

3 0
3 years ago
How much work can be done in 30 seconds by a 1000-watt microwave oven?
iris [78.8K]
Half of it can be be at 1000 watt microwave oven!!!                                                                                                                                                                                                                                                                                                            I hope it help!!!!!!
7 0
3 years ago
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What is the minimum time that a warm up should last
Vladimir [108]
5 minutes is the minimum time
7 0
3 years ago
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A rope vibrates every 0.5 s. What is the frequency of the waves? 5 Hz 2 Hz 0.5 Hz 1 Hz
yulyashka [42]
The answer is 2Hz

Using the formula f= 1/T we can plug in .5 for T and solve for frequency.
4 0
3 years ago
Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back dow
Zigmanuir [339]

The maximum rate at which energy can be added to the circuit element mathematically given as

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

<h3>What is the maximum rate at which energy can be added to the circuit element?</h3>

Generally, the equation for P is  mathematically given as

P=\ln s \frac{\Delta T}{\Delta t}

Therefore

Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}

\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}

\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}

Max temp Change

MaxT=5.6^{\circ} \mathrm{C}

\text { time }=3 \times 60

t=180s

In conclusion, Max Energy Rate

MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

Read more about  Energy

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