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3 years ago

10

Urgent!

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Answer:

See explanation

Step-by-step explanation:

From the graph,

After 1 hour passed, 2 inches of show fell
After 5 hours passed, 10 inches of snow fell
And so on

This means, that points (1,2), (5,10) lie on the graph. This graph passes through the origin, so its equation is

$y=kx,$

where k is the slope

Find k:

$2=k\cdot 1\\ \\k=2,$

so the equation is $y=2x$ and the slope is k = 2.

The slope means how many inches of snow fell in 1 hour.

In 1 hour, 2 inches of snow fell.

You might be interested in

For positive acute angles AA and B,B, it is known that \tan A=\frac{28}{45}tanA= 45 28 and \cos B=\frac{3}{5}.CosB= 5 3 . Fi

MrRa [10]

Answer:

$\cos(A + B) = \frac{23}{265}$

Step-by-step explanation:

Given

$\tan A=\frac{28}{45}$

$\cos B=\frac{3}{5}$

Required

$\cos(A+B)$

In trigonometry:

$\cos(A+B) = \cos\ A\ cosB - sinA\ sinB$

We need to solve for cosA, sinA and sinB

Given that:

$\tan A=\frac{28}{45}$ and the tangent of an angle is a ratio of the opposite side (x) to the adjacent side (y),

So, we have:

$x =28$ and $y = 45$

For this angle A, we need t calculate its hypotenuse (z).

Using Pythagoras,

$z^2 = x^2 + y^2$

$z = \sqrt{x^2 + y^2$

$z = \sqrt{28^2 + 45^2$

$z = \sqrt{2809$

$z = 53$

From here, we can calculate sin and cos A

$\sin A= \frac{opposite}{hypotenuse}$ and $\cos A= \frac{adjacent}{hypotenuse}$

$\sin A= \frac{x}{z}$

$\sin A= \frac{28}{53}$

$\cos A= \frac{y}{z}$

$\cos A= \frac{45}{53}$

To angle B.

Give that

$\cos B=\frac{3}{5}$ and the cosine of an angle is a ratio of the adjacent side (a) to the hypotenuse side (c),

So, we have:

$a = 3$ and $b = 5$

For this angle B, we need to calculate its opposite (b).

Using Pythagoras,

$c^2 = a^2 + b^2$

$5^2 = 3^2 + b^2$

$25 = 9 + b^2$

Collect like terms

$b^2 = 25 - 9$

$b^2 = 16$

$b = \sqrt{16$

$b = 4$

From here, we can calculate sin B

$\sin B= \frac{opposite}{hypotenuse}$

$\sin B = \frac{b}{c}$

$\sin B = \frac{4}{5}$

Recall that:

$\cos(A+B) = \cos\ A\ cosB - sinA\ sinB$

and

$\cos B=\frac{3}{5}$ $\sin B = \frac{4}{5}$ $\sin A= \frac{28}{53}$ $\cos A= \frac{45}{53}$

$\cos(A + B) = \frac{45}{53} * \frac{3}{5} - \frac{28}{53} * \frac{4}{5}$

$\cos(A + B) = \frac{135}{265} - \frac{112}{265}$

$\cos(A + B) = \frac{135-112}{265}$

$\cos(A + B) = \frac{23}{265}$

7 0

3 years ago

Which expression is equivalent to 1/√121x^9y^8z^10

sweet [91]

Answer:

1/(11 x^(9/2) y^4 z^5)

or

sqrt(x)/ 11 x^5 y^4 z^5

Step-by-step explanation:

1/ sqrt(121x^9y^8z^10)

Lets simplify the denominator

sqrt(121x^9y^8z^10)

Break it into pieces

sqrt(121) sqrt(x^9) sqrt(y^8) sqrt(z^10)

11 sqrt (x^8) sqrt(x) y^4 z^5

11 x^4 y^4 z^5 * sqrt(x)

Putting this back in

1

----------------------------

11 x^4 y^4 z^5 * sqrt(x)

But we dont want a sqrt root in the denominator

Multiply by sqrt(x)/sqrt(x)

sqrt(x)

----------------------------

11 x^4 y^4 z^5 * sqrt(x) sqrt(x)

sqrt(x)

----------------------------

11 x^4 y^4 z^5 * x

sqrt(x)

----------------------------

11 x^5 y^4 z^5

7 0

3 years ago

in order to receive a b on an essay, the grade must be no lower then 82% and no higher than an 89%.write a compound inequality t

fomenos

Answer:

0.82 ≤ x ≤ 0.89

Step-by-step explanation:

hope this helps, pls mark brainliest :D

7 0

3 years ago

2 questions<br> when can you combine like terms?<br> when can you NOT combine like terms?

Rainbow [258]

*just a guess*

you can combine like terms when they are using the same variables or constants. ex: you can combine 34x and 76x because of the variable

6 0

3 years ago

Help please help!! my grade is down

lisov135 [29]

plug in -2 for x

7*-2 -10 = -24

7 0

3 years ago