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cupoosta [38]
3 years ago
10

Can someone please help me I really need help please help me

Mathematics
1 answer:
Step2247 [10]3 years ago
4 0

Answer:

60

Step-by-step explanation:

if it went down one more it would be 30

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ONLY ANSWER NO WORK WILL MARK BRAINLIEST
Whitepunk [10]
Alright, here goes:
For this question, you are asked about the median and Interquartile Range(IQR), so first you need to understand what that means.
The IQR is the box in the middle of the box-and-whisker-plot. The question asks for the place to have a small IQR, so the most likely places are Pensacola and Jacksonville.
The question is also asking for a high median temperature. The median is the line in the middle of the plot.
The median of Pensacola's plot is higher than the median of Jacksonville, so Pensacola Beach is your answer :)
5 0
3 years ago
Can someone explain how to solve this question:
Svetach [21]

Answer: The answer is 51 degrees


Step-by-step explanation:


8 0
3 years ago
Slope is 0 and (3,2) is on the line
USPshnik [31]

Answer:

y = 2

Step-by-step explanation:

if slope is 0 y stays the same and y is 2 on the point

7 0
3 years ago
Given that f(x) = 4x√3x + 3 and g(x) = 2√x+1, find (f/g)(x)
Tresset [83]

Answer:

2x\sqrt{3}.

Step-by-step explanation:

\frac{f}{g}(x)=\frac{4x\sqrt{3x+3}}{2\sqrt{x+1}}=\frac{2*2*x*\sqrt{3}*\sqrt{x+1}}{2*\sqrt{x+1}}=2x\sqrt{3}.

8 0
2 years ago
A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,
Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

So

P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017

Probability of a defective item being produced on the first shift:

1% of 50%. So

P(A \cap B) = 0.01*0.5 = 0.005

What is the probability that it was manufactured during the first shift?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0
2 years ago
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