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2 years ago

8

Determine if the given value makes the equation true or false. For x3 – 8 = 15, if x = 69

2 answers:

Margaret [11]2 years ago

7 0

Answer:

False

Step-by-step explanation:

69 * 3 =207

207 - 8 = 199

x3 - 8 = 199 for x = 69

MrRa [10]2 years ago

6 0

Answer:

(69)(3)−8 = 15

199≠15

False

Step-by-step explanation:

hope it helps, 69(3) is already bigger than 15, then -8 makes it 199, which is definitely not equal to 15.

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Mr. Abraham is 36 years old. His wife is 6 years younger than him and their son is 24 years old younger than his wife. What is t

sesenic [268]

Hi!
We know that Mr. Abraham’s wife is 6 years younger than him, which is 36-6, which means his wife is 30 years old.

We also know that Mr A’s son is 24 years younger than his wife, which is 30-24, which is 6.

As of right now, we now know that:
Mr. A is 36
Mr. A’s wife is 30
Mr. A’s son is 6

It’s asking for the ratio of Him:Wife:Son, so 36:30:6.

BUT, it’s asking for simplest form, so divide each of those numbers by 6.

Your answer is: 6:5:1

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3 years ago

Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).

EleoNora [17]

Answer:

Step-by-step explanation:

There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.

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2 years ago

Two numbers have a sum of 136 and a difference of 32. Find the smaller of the two numbers.

Leno4ka [110]

Answer:

52

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is 4323x - 78487 = 5693<br> 25 POINTS

poizon [28]

4323x - 78487 = 5693

4323x = 5693 - 78487

4323x = -72794

x = -72794/4323

x = -16.8387694

3 0

3 years ago

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4. Two cards are selected from a regular deck of cards. If the first was a ten, determine the probability that the second was a

ioda

Answer:

a) $P=\frac{1}{221}$

b) $P=\frac{4}{663}$

c) $P=\frac{4}{221}$

Step-by-step explanation:

Given : Two cards are selected from a regular deck of cards. If the first was a ten.

To determine : The probability that the second was a (a) ten, (b) jack, (c) picture card ?

Solution :

Total number of cards = 52 in which there are 4 sets of 13 cards with two different color.

We are drawing two card one after another without replacement.

Probability of drawn first card 10 is $P(T_1)=\frac{4}{52}=\frac{1}{13}$

a) Second card drawn is 10,

Probability of drawn second card 10 is $P(T_2)=\frac{3}{51}=\frac{1}{17}$

Total probability that first card was 10 and second card is 10,

$P=P(T_1)\times P(T_2)$

$P=\frac{1}{13}\times \frac{1}{17}$

$P=\frac{1}{221}$

b) Second card drawn is Jack,

Probability of drawn second card Jack is $P(J)=\frac{4}{51}$

Total probability that first card was 10 and second card is Jack,

$P=P(T_1)\times P(J)$

$P=\frac{1}{13}\times \frac{4}{51}$

$P=\frac{4}{663}$

c) Second card drawn is picture card,

Number of picture card is 4j's, 4Q's, 4K's = 12

Probability of drawn second card picture card is $P(p)=\frac{12}{51}=\frac{4}{17}$

Total probability that first card was 10 and second card is picture card,

$P=P(T_1)\times P(p)$

$P=\frac{1}{13}\times \frac{4}{17}$

$P=\frac{4}{221}$

7 0

3 years ago