Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
Answer:
hghjghgjh
Step-by-step explanation:
Answer:
the bottom right one
Step-by-step explanation:
Answer:
The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)
<u>Solution:</u>
Given, equation is 
We have to find the vertex of the given equation.
When we observe the equation, it is a parabolic equation,
We know that, general form of a parabolic equation is
Where, h and k are x, y co ordinates of the vertex of the parabola.

By comparing the above equation with general form of the parabola, we can conclude that,
a = -6, h = 1 and k = 9
Hence, the vertex of the parabola is (1, 9).