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otez555 [7]
3 years ago
13

A stock has a Price/Earnings Ratio (P/E) of 4.5. Earnings per share (EPS) of these stocks is 8. What is the stock’s market value

?
A.
$14
B.
$25
C.
$36
D.
$81

E.
$40
Mathematics
2 answers:
lakkis [162]3 years ago
8 0
Answer is going to be C. 36$
zzz [600]3 years ago
7 0

Answer:

$36

Step-by-step explanation:

giohvitixkgxufxyrYrzufzgxkhyd8rtcochyixyixustifyi

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Leviafan [203]
It would be 11 if I’m reading this right
8 0
3 years ago
A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0
3 years ago
3(x - 2) - (1 - x) > 2x - 7
Kipish [7]

Answer:

56

Step-by-step explanation:

a square meters are a rectangle is the place where the people who cares about their own business is not a rectangle is a rectangle is a rectangle is a square and the area is not the only thing to the most of the time that you have been doing this and that is the only thing I have been doing with the past few years I've had to do it myself for

7 0
2 years ago
A palm tree is supported by two guy wires as shown in the diagram below.
garri49 [273]

Answer:

I think it's a or b the picture is fuzzy

8 0
3 years ago
3-4 litros de jugo de frutilla 1 y 1-2 litros de jugo de manzana 1-8 litro de jugo consentrado de limón . 1 y 1-2 litro de agua.
Neko [114]

Answer:

Hay 3,875 litros de jugo multifrutal.  

Step-by-step explanation:

<em>(Se asume que el problema fue propuesto en un país distinto a los Estados Unidos, razón por la cual se emplea las reglas del Sistema Internacional.)</em>

La capacidad de jugo multifrutal en el bidón se obtiene con la mezcla de cada jugo frutal y se logra mediante la suma de cada capacidad. A partir del enunciado, tenemos que la capacidad del jugo multifrutal es:

V = \frac{3}{4}\,L + 1\,\frac{1}{2}\,L + \frac{1}{8}\,L + 1\,\frac{1}{2}\,L

V = \frac{3}{4}\,L + 1\,L + \frac{1}{2}\,L + \frac{1}{8}\,L + 1\,L + \frac{1}{2}\,L

V = 3,875\,L

Hay 3,875 litros de jugo multifrutal.  

5 0
3 years ago
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