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Dennis_Churaev [7]
3 years ago
12

A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the end of the

rope back and forth with a frequency of 4 Hz, the transverse wave you produce has a wavelength of 0.5 m. What is the speed of the wave in the rope?a. 0.13 m/sb. 8 m/sc. 2 m/sd. 4 m/s
Physics
1 answer:
Strike441 [17]3 years ago
7 0

Answer:

c. 2 m/s

Explanation:

The relationship between speed, frequency and wavelength of a wave is given by:

v=f \lambda

where

v is the speed of the wave

f is its frequency

\lambda is the wavelength

For the transverse wave in this problem, we have:

f = 4 Hz is the frequency

\lambda=0.5 m is the wavelength

Substituting these numbers into the equation, we find the speed of the wave:

v=(4 Hz)(0.5 m)=2 m/s

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I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
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How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
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100 Watts

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<u>These equations are needed to work out the answer:</u>

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An important dimensionless parameter in certain types of fluid flow problems is the Froude number defined as V/√g.l where V is a
prohojiy [21]

Answer:

1.24611

Explanation:

V = Velocity = 10 ft/s

L = Length = 2 ft

g = Acceleration due to gravity = 32.2 ft/s²

Froude number is given by

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10}{\sqrt{32.2\times 2}}\\\Rightarrow Fr=1.24611

Converting to SI units

10\ ft/s=10\times \dfrac{1}{3.281}

32.2\ ft/s^2=32.2\times \dfrac{1}{3.281}

2\ ft=2\times \dfrac{1}{3.281}

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10\times \dfrac{1}{3.281}}{\sqrt{32.2\times \dfrac{1}{3.281}\times 2\times \dfrac{1}{3.281}}}\\\Rightarrow Fr=1.24611

The Froude number is 1.24611

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