The mixture flow rate in lbm/h = 117.65 lbm/h
<h3>Further explanation</h3>
Given
15.0 wt% methanol
The flow rate of the methyl acetate :100 lbm/h
Required
the mixture flow rate in lbm/h
Solution
mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :
mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :
Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.
1 kg mixture = 0.85 .methyl acetate
So flow rate for mixture :
Given buffer:
potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )
[KHC4H4O6] = 0.0451 M
[K2C4H4O6] = 0.028 M
Ka1 = 9.2 *10^-4
Ka2 = 4.31*10^-5
Based on Henderson-Hasselbalch equation;
pH = pKa + log [conjugate base]/[acid]
where pka = -logKa
In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2
pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]
= -log (4.31*10^-5) + log [0.0451]/[0.028]
pH = 4.15
Answer: For many calculators, including the TI –83 and TI 83 Plus, the [EE] button is used to enter scientific notation. The [EE] button can be found in yellow above the comma key [,].
Answer:
Explanation:Rocks are heated and melt.
Some magma move sideways in opposite directions.Magma cools and sinks.Magma expands and rises at divergent boundaries.Magma expands and rises at divergent boundaries.
As Bond energy is between carbon and oxygen the is 358 for a single bond of C-0 and 745 for a double bond is the c=0.
- In the first step the one atom pulls the electron from another atom
. In the second step that is forming bonds releases energy and is the exothermic
. In the third step they pull electrons away from other elements
.
- In the last step the additional bonds is needed more energy to make or break, so the bond energy is very higher Hence the -153.
Learn more about the energy between carbon and oxygen is 358.
brainly.com/question/26244428.
