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3 years ago

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Which statement about fusion reactors is true? a Enriched uranium isotopes are used as fuel in fusion reactors. b Fuel for fusio

n reactors can be extracted form ocean water. c Fusion reactors are now replacing fission reactors. d Fusion reactors produce radioactive waste as spent fuel .

1 answer:

trapecia [35]3 years ago

6 0

Answer:

b Fuel for fusion reactors can be extracted from ocean water.

Explanation:

The fuel is deuterium, which makes up 0.02% of the hydrogen atoms in water. The oceans contain more than a billion cubic kilometres of water, so that's a lot of deuterium.

a is wrong. The fuel for fusion reactors is deuterium.

c is wrong. There is much research, but there are no large-scale fusion reactors in operation.

d is wrong. Fusion reactors do not produce radioactive waste as spent fuel. Most of the radioactive waste would be the reactor core itself.

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3 years ago

You are on the Titanic and want to find something that will float because you didn't

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Find volume of pillow

L=78cm

B=55cm

H=25cm

$\\ \bull\tt\longrightarrow V=LBH$

$\\ \bull\tt\longrightarrow V=25(78)(55)$

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$\\ \bull\tt\longrightarrow V=10.72m^3$

Now

Mass=5.5kg

$\\ \bull\tt\longrightarrow Density=\dfrac{Mass}{Volume}$

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As it is less than density of water it will float on water

8 0

3 years ago

Which statement describes the 3d, 4s, and 4p orbitals of Arsenic (As) based on its electronic configuration and position in the

tekilochka [14]

Answer:

The 3d and 4s orbitals are completely filled, and the 4p orbital is partially filled.

Explanation:

8 0

3 years ago

How many grams of tin would occupy 5.5 L if it had a density of 7.265

lisabon 2012 [21]

In order to find the mass of tin with the given volume of 5.5 L and density of 7.265, we will use the formula
Density = Mass / Volume

We will just multiply both sides of the equation by the volume and we will get:
Mass = Volume x Density

We can now solve the problem by substituting the given.

Mass = 5.5 L x 7.265 g/L
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7 0

3 years ago

Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and

Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

The given data is as follows.

mass = 500 g, $C_{p}$ = 24.4 J/mol K

$T_{h}$ = 500 K, $T_{c}$ = 250 K

Mass number of copper = 63.54 g /mol

Number of moles = $\frac{mass}{/text{\molar mass}}$

= $\frac{500}{63.54}$

= 7.86 moles

Now, equating the entropy change for both the substances as follows.

$7.86 \times 24.4 \times [T_{f} - 250]$ = $7.86 \times 24.4 \times [500 -T_{f}]$

$T_{f} - 250 = 500 - T_{f}$

$2T_{f}$ = 750

So, $T_{f}$ = $375^{o}C$

For the metal block A, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{500}]$

= -3.04 J/ K mol

For the block B, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{250}]$

= 4.296 J/Kmol

And, total entropy change will be as follows.

= 4.296 + (-3.04)

= 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.

8 0

3 years ago