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slega [8]
3 years ago
11

What does the stonefish eat

Chemistry
1 answer:
solmaris [256]3 years ago
5 0
Croat or stones stones
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The fundamental particles of protons and neutrons are called....
zaharov [31]
The Answer is C) Quarks
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3 years ago
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For the chemical reaction 2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq) write the net ionic equation, including the phases.
Crazy boy [7]

Answer:

2H⁺(aq) + 2OH⁻(aq)  --> 2H2O(l)

Explanation:

2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq)

We break the compounds into ions. Only compounds in the aqueous form can be turned into ions.

The ionic equation is given as;

2H⁺(aq)  +  2Br⁻(aq)  + Ba²⁺(aq) + 2OH⁻(aq)   --> 2H2O(l)  +  Ba²⁺(aq)  + 2Br⁻(aq)

Upon eliminating the spectator ions; The net equation is given as;

2H⁺(aq) + 2OH⁻(aq)  --> 2H2O(l)

8 0
3 years ago
Please Which one??? is it???
Tatiana [17]
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Your computer is an example of which type of energy? Question options: Nuclear Kinetic Light All of the above
xz_007 [3.2K]

<u>Answer</u>:  Light

<em>Computer is an example of light energy which is the third option out of the given four choices. </em>

<u>Explanation:</u>

We know how a computer works it takes in <em>the electrical energy</em> and does a <em>lot of mathematical mechanical work</em> and for giving answers. It uses a screen on which light blinks in pattern such that it represents letters or mathematical numbers or expressions.

Hence by using this statement we can say <em>computer converts electrical energy into light energy. </em>

4 0
3 years ago
The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A
Mamont248 [21]

Answer:

The  K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for B(g) = \frac{1}{2}A

            K_c=[B]^2[A]

                 = 0.045

The reverse will be 2B\leftrightharpoons A

Then,      K_c = \frac{[A]}{[B]^2}

                    =  \frac{1}{0.045}

                    = 22m^{-1}

The equilibrium constant for B(g) = \frac{1}{2}A will be

               K_c = \sqrt{K_c}

                    =\sqrt{22}

                    = 4.69

Therefore, K_c for the reaction B(g) = \frac{1}{2}A will be 4.69.

5 0
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