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lyudmila [28]
3 years ago
13

The box plot show the lengths of the songs on two digital music players in minutes .Which statement is best supported by the inf

ormation in the box plots ?
Mathematics
1 answer:
kakasveta [241]3 years ago
4 0

Solution :

In the figure, the box plot represents the lengths of the songs of the two digital music players that is in minutes.

From the figure, we can see that for the music player Y, the interquartile range of the data is small.

And the interquartile range of data is more for the music player X.

So, we can conclude that the interquartile range of data is greater for Music player X than the interquartile range data of music player Y.

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X over 2 +2= 15 two step equations
Fed [463]

Answer:

\boxed{\boxed{\sf x=84}}

Step-by-step explanation:

\sf \cfrac{x}{6} +2=16

<u>Multiply both sides of the equation by 6:</u>

\sf x+12=96

<u>Subtract 12 from both sides:</u>

\sf x=96-12

<u>Subtract 12 from 96:</u>

\sf x=84

<u>_________________________________</u>

3 0
2 years ago
Read 2 more answers
This will be so helpful right now thank
RoseWind [281]

Answer:

55 ft.

Step-by-step explanation:

First find the area of Lot X

67 • 70 = 4,690

Subtract the are of Lot X from the total area

8,375 - 4,690 = 3,685

3,685 is the area of Lot Y

Now divide 3,685 by the length of Lot Y : 67

3,685 ÷ 67 = 55

The width of Lot Y is 55 ft.

Hope this helps!

5 0
3 years ago
Dan made $5000 in taxable income last year.
storchak [24]

well, we know is 10% for the first 7500, but Dan only made 5000 of taxable income, so he's in that range of 0 - 7500, so he only gets to pay 10% of 5000.

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 5000}}{\left( \cfrac{10}{100} \right)5000}\implies 500

8 0
2 years ago
Is (0, 3) a solution to the following system?
daser333 [38]

Solve each equation with (0, 3)

y = -x + 3

3 = -0 + 3

y = 3 (correct since y = 3 in (0, 3))

y = 2x - 3

3 = 2(0) - 3

3 = 0 - 3

3 = -3 (incorrect since it isn't equal)

So... No, because it does not check in the second equation.

Best of Luck!

6 0
3 years ago
A chemical refinery needs a vat. They want the vat to be a rectangular prism (with square bases) that has a maximum volume of 1,
Alex17521 [72]

Answer:

For least material to be used lengths of square base and sides = 10 units.

Step-by-step explanation:

Let the lengths of the square base and the sides = x feet, x feet and y feet

Area of the square base = x² feet

Volume of the rectangular prism = Area of the square base × Height

                                                      = x²y cubic feet

1000 = x²y

y = \frac{1000}{x^2} -------(1)

Material used in the prism = Surface area of the rectangular prism

                                            = 2(lb + bh + hl)

Here, h =  height of the prism

l = length of the base

w = Width of the base

Material to be used (S) = 2(xy + x² + xy) - Area of lid

                                  S = 2(x² + 2xy) - x²

                                  S = x² + 2xy

Now by substituting the value of y from equation (1),

S = x² + 2x(\frac{1000}{x^{2} })

  = x² + \frac{2000}{x}

For least amount of material used,

We will find the derivative of the given function and equate it to zero.

S' = 2x - \frac{2000}{x^{2} }

2x - \frac{2000}{x^{2} } = 0

2x³ = 2000

x³ = 1000

x = 10 feet

From equation (1),

y = \frac{1000}{(10)^2}

y = 10 feet

Therefore, for least amount of the material used lengths of square base and sides will be 10 feet.

7 0
3 years ago
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