The box plot show the lengths of the songs on two digital music players in minutes .Which statement is best supported by the inf
1 answer:
Solution :
In the figure, the box plot represents the lengths of the songs of the two digital music players that is in minutes.
From the figure, we can see that for the music player Y, the interquartile range of the data is small.
And the interquartile range of data is more for the music player X.
So, we can conclude that the interquartile range of data is greater for Music player X than the interquartile range data of music player Y.
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Answer:
-4 4 4.5 8 20.5 32
Step-by-step explanation:
f g(x) = f(g(x))
Given, f(x) = 2x²
and g(x) = x - 2
Now f(g(x)) = f(x - 2) = 2(x - 2)²
We know that (a - b)² = a² - b² + 2ab
Using this we expand f(g(x)). We get:
f(g(x)) = 2{x² - 4x + 4}
Similarly, g(f(x)) = g(2x²) = 2x² - 2
Now, f(g(-2)) = 2[(-2)² - 4(-2) + 4] = 2(16) = 32.
Also, g(f(-2)) = 2[(-2)² - 2] = 2(2) = 4.
f(g(3.5)) = 2{(3.5)² -4(3.5) + 4} = 2[12.25 - 14 + 4] = 2(2.25) = 4.5.
g(f(3.5)) = 2{(3.5)² -2} = 2{12.25 - 2} = 2(10.25) = 20.5.
f(g(0)) = 2{0 - 4(0) + 4} = 2(4) = 8.
g(f(0)) = 2{0 - 2} = 2(-2) = -4.
Arranging them in ascending order, we get:
-4 4 4.5 8 20.5 32 would be the sequence.
A number b increased by 3 is greater than or equal to -26: