Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
No because the atomic mass is the average of the different isotopes, so there is no isotope with a mass of 35.45. There are no isotopes that have decimal masses, they have to be a whole number.
We first need to find the mass of bromine through the equation:
mass = moles * relative molecular mass = 0.95 mol * 160 g/mol = 152 g
We can then find the volume of this liquid through the equation:
volume = mass / density = 152 g / 3.12 g/mL = 48.7 mL
Hope this helps!
