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torisob [31]
3 years ago
11

Which organisms are producers in a temperate coniferous forest? (Select all that apply.)

Chemistry
2 answers:
viva [34]3 years ago
7 0
Grasses. Hope this helps!! Have a great day
Tju [1.3M]3 years ago
4 0

Answer:Coniferous trees, like pine, spruce, and fir, are the main producers in the forest. Their pine needles fall to the forest floor, creating a spongy mat for other life to inhabit. Low lying shrubs and moss are other producers in this ecosystem. Producers in the coniferous forest.

Explanation:

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A student is measuring the volumes of nectar produced by a flowering plant for an experiment. He measures nectar from 50 flowers
VARVARA [1.3K]

Answer:

His measurements will be more precise if he uses a graduated cylinder that measures to the nearest tenth of a mL.

Explanation:

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3 years ago
Hello! Can you please help me do this question? I have to pick two but I’m not really sure what to pick..
In-s [12.5K]

Answer:

B and D

Explanation:

it is B and D because in no gravity  if you change the size of the ball it does not change anything. and if you swing fast it does not change anything but the speed. if you change the angle it is just the same modle but different angle

7 0
3 years ago
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Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

    102.5 = [(\frac{1}{2})x + 498] - [(2)(243)]

    102.5 = (\frac{1}{2})x + 498 - 486

     102.5 - 12 = \frac{x}{2}

           x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

              x = [(\frac{1}{2})181 + (\frac{1}{2})498] - 243

                 = 339.5 - 243

                 = 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
An electromagnetic wave has a wavelength of 0.12 meters. what is that in nanometers?
tino4ka555 [31]

Answer:

1.2 × 10⁸ m

Explanation:

You want to convert metres to nanometres.

Recall that the multiplying prefix nano- means × 10⁻⁹, so

1 nm = 1 × 10⁻⁹ m

The conversion factor is either \frac{\text{1 nm} }{10^{-9} \text{m}} or \frac{10^{-9} \text{m} }{\text{1 nm}}.

You choose the one that has the desired units (nm) on top. Then

\lambda = \text{0.12 m} \times \frac{\text{1 nm} }{10^{-9} \text{m}} = 1.2 \times 10^{8} \text{ nm}

7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
nevsk [136]

Answer:

16. Option c.

Explanation:

The reaction is:

C₈H₁₈ + O₂  →  CO₂ + H₂O

Let's count, we have 8 C, 18 H and 2 O in reactant side

We have 1 C, 2 H and 3 O  in product side

In order to balance the C, we add 8 to CO₂ and to balance the H, we add a 9 to H₂O

Now we have 8 C on both sides and 18 H On both sides. Finally we have 25 O on product side.

C₈H₁₈ + O₂  →  8CO₂ + 9H₂O

To balance the O in product side we must add 25/2, but as it is a rational number, we must multiply x2 to get an integer number (x2 in all the stoichiometry). The balanced reaction is :

2C₈H₁₈ + 25O₂  →  16CO₂ + 18H₂O

with 16 C, 36 H and 50 O, on both sides

7 0
3 years ago
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