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BabaBlast [244]
4 years ago
7

PLEASE HELP ITS DUE TODAY!!! Write an equation in which the quadratic expression 2x^2-2x 12 equals 0. Show the expression in fac

tored form and explain what your solutions mean for the equation. Show your work.
Mathematics
1 answer:
stepladder [879]4 years ago
3 0

This is the function

{2x}^{2}  - 2 {x}^{1}  + 12

Then factor 2 out

2(x^2- x + 6) = 0

Divide both side by two and use the quadratic formula to get the following

(x - 3)(x + 2) = 0

X=3 And x=-2 and don't forget to Chek them

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Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.
muminat

Answer:

1. 12x^2-13.4x-11

- Degree: 2

- Number of terms: 3

2. 7x^3+168

 - Degree: 3

- Number of terms: 2

3. 9x^4-9

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

1. Given:

(4x + 2.2)(3x - 5)

Apply the Distributive property:

=12x^2+6.6x-20x-11

Add the like terms:

=12x^2-13.4x-11

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

(-304 +503 - 12) + (7x^3 - 25 + 6)

Add the like terms:

=187 + 7x^3 - 25 + 6=7x^3+168

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

(3x^2 - 3)(3x^2 + 3)

Apply Distributive property:

=9x^4-9x^2+9x^2-9

Add the like terms:

=9x^4-9

You can idenfity that:

- Degree: 4

- Number of terms: 2

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If you worked for 6 days and had a 50 dollar in your bank account, the M will represent how much money you have.
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1 , 3 , 6 , 10 , 15
Bas_tet [7]

First difference,

\Delta_{1} =  a_{2} - a_{1} = 3 - 1 = 2 = 1  + 1

Second difference,

\Delta_{2} =  a_{3} - a_{2} = 6 - 3 = 3 = 2 + 1

Third difference,

\Delta_{3} =  a_{4} - a_{3} = 10 - 6 = 4  = 3 + 1

And so on.

Assuming the pattern holds on, we see that

i-th difference,

\Delta_{i} =  a_{i + 1} - a_{i} = i + 1

\implies a_{i + 1} = a_{i}  +  i +  1

Then, nth term is,

\implies a_{n} = a_{n - 1} + n

= a_{n - 2}+ (n  + (n - 1))

= a_{n - 3} + (n + (n - 1) +(n - 2))

= a_{n - (n - 1)} + \sum \limits^{n - 2}_{k = 0}(n - k)

= a_1 + \sum \limits^{n - 2}_{k = 0}n-  \sum \limits^{n - 2}_{k = 0}k

= a_1 +n(n -2 + 1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +n(n -1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +(n -1 )(n-  \frac{1}{2} (n - 2))

= a_1 + \frac{1}{2} (n -1 )(2n- n  +  2)

= a_1 + \frac{1}{2} (n -1 )(n  +  2)

\implies a_{n} = 1 + \frac{1}{2} (n -1 )(n  +  2)

Now, the 21st term in the sequence is,

\implies a_{21} = 1 + \frac{1}{2} (21 -1 )(21  +  2)

= 1 + \frac{1}{2}  \times 20 \times 23

= 231

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3 years ago
Which expressions are equivalent to 70 × 5.3
marin [14]

Answer:

35 x 10.6, 140 x 2.65 and 371 x 1

Step-by-step explanation:


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4 years ago
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