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It would be 2/10, or 1/5, since two out of the 10 numbers are even. 2/10 simplifies to 1/5, since there is 1 for every 5 numbers.
We could turn this into a percentage by dividing 1 by 5, which gives us 0.2. Then we can multiply by 100 to get 20.
So, our probability of choosing an even number is:
2/10
OR
1/5
OR
20%
Hope I could help!
The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars
<h3>Arithmetic sequence</h3>
- First month, a = 4,600 cars
- Common difference, d = -50 cars
First five terms;
a = 4,600
a + d = 4600 + (-50)
= 4600 - 50
= 4,550
a + 2d
= 4600 + 2(-50)
= 4600 - 100
= 4,500
a + 3d
= 4,600 + 3(-50)
= 4,600 - 150
= 4,450
a + 4d
= 4600 + 4(-50)
= 4,600 - 200
= 4,400
cars predicted for the twelfth month.
a + 11d
= 4600 + 11(-50)
= 4600 + 550
= 4,050
Total predicted number of sold cars for the first year:
Sn = n/2{2a + (n - 1)d }
= 12/2{2×4600 + (12-1)-50}
= 6{9200 + 11(-50)}
= 6(9,200 - 550)
= 6(8,650)
= 51,900 cars
Learn more about arithmetic sequence:
brainly.com/question/6561461
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<span>If m = 7x + 7, m = 4y, and m = 112
since m = 112
112 = 7x + 7
112 - 7 = 7x
105= 7x
x = 15
112 = 4y
y = 28</span>
Here is the graph, you can match it yourself:
