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ioda
3 years ago
9

Write an equation in slope-intercept form of the line shown.

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

y = 2x - 5

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2

m = 2

Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in y = mx + b

-3 = (2)(1) + b

-3 = 2 + b

Subtract 2 from both sides

-3 - 2 = 2 + b - 2

-5 = b

b = -5

Plug in the value of m and b into the slope-intercept form equation, y = mx + b.

Thus:

y = 2x +(-5)

✅y = 2x - 5

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Given a line with equation 3x +7y = 21. write an equation in point-slope form of the line parallel to the given line through the
guapka [62]

Answer:

The equation of the line is y = -3/7x - 23/7

Step-by-step explanation:

To start we need to find the slope of the original line. We can do this by solving the equation for y.

3x + 7y = 21

7y = -3x + 21

y = -3/7x + 3

Now we know the slope to be -3/7. Since parallel lines have same slopes, we know the new line also will have a -3/7 slope. We can now use that along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 5 = -3/7(x - 4)

y + 5 = -3/7x + 12/7

y = -3/7x - 23/7

8 0
2 years ago
Brainliest for correct answer !! :)<br> f (x) = 3x - 5 g (x) =2^x Find f^-1 (x)
katovenus [111]

Answer:

f^-1(x) = (x +5)/3

also = 1/3 x + 5/3

Step-by-step explanation:

Just to be clear, the ^-1 has nothing to do with negative exponents. It just unfortunately looks the same as a negative exponent.

Anyway, there's three basic steps. First write y instead of f(x). Then switch the x and y. Then solve for y.

f(x) = 3x - 5

write y in place of f(x).

y = 3x - 5

SWITCH x and y.

x = 3y - 5

SOLVE for y.

-3y + x = -5

-3y = -x - 5

y = (-x - 5)/-3

y = (x + 5)/3

OR

y = (1/3)x + 5/3

f^-1(x) = 1/3 x + 5/3

3 0
2 years ago
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