The range of the function 8x + y = -3 at the domain {−3, 1, 2, 4} is {21, -11, -19, -35}
<h3>How to determine the range of the function?</h3>
From the question, we have the following equation that can be used in our computation:
8x + y = -3
Start by making the variable y the subject of the formula
So, we have
y = -8x - 3
Using the domain = {−3, 1, 2, 4} the values in the range are calculated as follows
y = -8 x -3 - 3 = 21
y = -8 x 1 - 3 = -11
y = -8 x 2 - 3 = -19
y = -8 x 4 - 3 = -35
When these values are combined, we have the notation to be:
{21, -11, -19, -35}
So, the range is {21, -11, -19, -35}
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<u>Complete question</u>
What is the answer to this question? 8x+y=-3
domain = {−3, 1, 2, 4}
Write the range of y using set notation.
The answer is m=3/4 hope this helps
Answer:
D.5/1
Step-by-step explanation:
5\1 is just 5 in fraction form
The 2 widths make 2x
<span>The length is (7000 - 2x) (not just x)
</span>Area = (7000 - 2x) * x
<span>Area = 7000x - 2x^2
</span>
Area = - 2(x^2 - 1,400x)
Area = -2 (x^2 - 1,400x + (1,400<span>/2)^2 ) + 7812.5 </span>
<span>Area = -2 (x - 62.6)^2 + 7812.5
</span>
The maximum area = 7812.5
<span>when </span>
<span>the width = 62.5 and </span>
<span>the length = 250 - 2*62.6 </span>
<span>the length = 250 - 125 </span>
<span>the length = 125</span>