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3 years ago

Under which of the following sets of conditions would the most o2 (g) be dissolved in h2o(l)?

Chemistry

1 answer:

jek_recluse [69]3 years ago

6 0

Answer:

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

Option B is correct.

Explanation:

Step 1: Data given

Pressure = 5 atm

Temperature = 20 °C or 80 °C

Step 2:

At low pressure, a gas has a low solubility. Decreased pressure allows more gas molecules to be present in the air, with very little being dissolved in solution. At high(er) pressure, a gas has a high solubility.

This means the higher the pressure the more the gas will dissolve. Since The pressure stays constant, it depends on the temperature.

The solubility of gases in liquids decreases with increasing temperature.

This means the gas will dissolve more with a lower temperature.

Oxygen will dissolve more in H2O at 5 atm and 20 °C than at 5 atm 80 °C

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Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

3 0

3 years ago

The number 4012 has how many significant figures?

grandymaker [24]

Answer:

8 figures.

Explanation:

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3 years ago

It is common for students to overshoot the endpoint, meaning they add too much NaOH(aq) from the buret, which causes the solutio

umka2103 [35]

Answer: the percentage of acetic acid will be low.

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Overshooting the end point is an error which can occur when the person involved in the the titration accidently goes beyond this endpoint by adding too much of the substance(base) from the burette into the beaker missing the exact endpoint.

This implies that the person has added too much of the burreted liquid, ie the base than required , making the acid in the beaker to continue to react resulting to a lower concentration of the acid (acetic acid) with excess base.(NaOH)

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3 years ago

The scientific notation 2 x 10-2 has what value? <br> 0.02<br> 0.002<br> 0.2<br> 0.0002

Marta_Voda [28]

Since the exponent is negative, you move the decimal (2.0) to the left two spots leaving you with .02

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3 years ago

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What happens to a gas that is enclosed in a rigid container when the temperature of the gas is increased?

yanalaym [24]

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