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Nookie1986 [14]
3 years ago
14

in a petri dish, a certain type of bacterium doubles in number every 30 minutes. there were originally 16, or 2^4, bacteria in t

he dish. after 150 minutes, the number of bacteria has doubled 7 times, multiplying by 2^7. Now the population of bacteria is 2^4 • 2^7. Expressed as a power, how many bacteria are in the petri dish after 150 minutes? A. 2^28 B. 2^11 C.4^11 D.2^7
Chemistry
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

D

Explanation:

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Answer:

Value of Q_{p} for the given redox reaction is 1.0\times 10^{-8}

Explanation:

Redox reaction with states of species:

14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)

Reaction quotient for this redox reaction:

Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of H_{2}O is taken as 1 due to the fact that H_{2}O is a pure liquid.

pH=-log[H^{+}]

So, [H^{+}]=10^{-pH}

Plug in all the given values in the equation of Q_{p}:

Q_{p}=\frac{(0.10)^{2}\times (0.010)^{3}}{(10^{-0.0})^{14}\times (1.0)\times (1.0)^{6}}=1.0\times 10^{-8}

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Formula used is as follows.

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