Answer:
4.90 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 125.0 mL
M₂ = 4.56 M
V₂ = 134.1 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
Substituting the respective values ,
M₁ * 125.0 mL = 4.56 M * 134.1 mL
M₁ = 4.90 M
The average density of the peat moss in units of g/cm³ is 2.52 g/cm³
<h3>How to convert 40 lb to grams (g)</h3>
We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:
1 lb = 453.592 g
Therefore,
40 lb = (40 × 453.592) / 1 lb
40 lb = 18143.68 g
<h3>How to convert 1.9 gal to cm³</h3>
We can convert 1.9 gal to cm³ as follow:
1 gal = 3785.41 cm³
Therefore,
1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal
1.9 gal = 7192.279 cm³
<h3>How to determine the density </h3>
The density can be obtained as follow:
- Mass = 18143.68 g
- Volume = 7192.279 cm³
- Density =?
Density = mass / volume
Density = 18143.68 / 7192.279
Density = 2.52 g/cm³
Learn more about density:
brainly.com/question/952755
#SPJ1
Answer:
Al + 4AgNO3 >>Al(NO3)3+ 3Ag
Explanation:
the number of moles of No3 of the products is 3 therefore we have to balance the reactants by adding 3 before the "AgNO3" which also leades us to adding 3 mols to Ag on the products side
Answer:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
Explanation:
By ideal gas equation:
Number of moles (n)
can be written as: 
where, m = given mass
M = molar mass
where,
which is known as density of the gas
The relation becomes:
.....(1)
We are given:
M = molar mass of chloroform= 119.5 g/mol
R = Gas constant = 
T = temperature of the gas = 
P = pressure of the gas = 1.00 atm
Putting values in equation 1, we get:
4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.
