Select all sets that contain the number 0.484848.

1 answer:

4 0

0.484848 . . . . .

A. Integer . . . no, it's not
B. Irrational . . . no, it's not
C. Natural. . . no, it's not
D. Rational . . . Yes ! It is !
E. Whole . . . no, it's not

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If the original number is 15 and the new number is 5, what is the percent decrease?

Arlecino [84]

When a quantity grows (gets bigger), then we can compute its PERCENT INCREASE:

[beautiful math coming... please be patient] PERCENT INCREASE=(new amount−original amount)original amountPERCENT INCREASE=(new amount−original amount)original amount

Some people write this formula with 100%100% at the end,
to emphasize that since it is percent increase, it should be reported as a percent.

So, here's an alternate way to give the formula:

PERCENT INCREASE=(new amount−original amount)original amount⋅100%PERCENT INCREASE=(new amount−original amount)original amount⋅100%

Recall that 100%=100⋅1100=1100%=100⋅1100=1 .
So, 100%100% is just the number 11 !
Multiplying by 11 doesn't change anything except the name of the number!
Hope this helps

6 0

3 years ago

-15= x/-0.5 8= what does x equal

Stels [109]

8*0.5*x=-15
x = -15/4

7 0

3 years ago

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer.

miss Akunina [59]

Answer:

$\frac{1}{990}$

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = $\frac{n!}{(n-r)!}$