P(most favorable outcome) = 1 -(0.03 +0.16 -0.01) = 0.82
_____
"repair fails" includes the "infection and failure" case, as does "infection". By adding the probability of "repair fails" and "infection", we count the "infection and failure" case twice. So, we have to subtract the probability of "infection and failure" from the sum of "repaire fails" and "infection" in order to count each bad outcome only once.
The probability of a good outcome is the complement of the probability of a bad outcome.
Keywords:
<em>equation, operations, equivalent, binomial, square root
</em>
For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.
So we have:

By definition:

Thus,
is equivalent to 
Answer:

Option D
I dont know the first answer but the 2nd is dad
A^3-19 should be the answer, good luck
I hope this helps you
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