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asambeis [7]
3 years ago
13

Suppose that a rectangular toroid has 2,000 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i

s h = 0.60 m, what is the current (in A) flowing through the rectangular toroid when the energy in its magnetic field is 4.0 ✕ 10−6 J?
Physics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

0.01154 A

Explanation:

We have given the energy in the magnetic field U=4\times 10^{-6}J

Value of inductance L =0.060 H

Energy stored in magnetic field is given by U=\frac{1}{2}Li^2

i=\sqrt{\frac{2U}{L}}

i=\sqrt{\frac{2\times 4\times 10^{-6}}{0.06}}=0.01154\ A

So the current flowing through rectangular toroid will be 0.01154 A

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Answer:

19,551 J!

Explanation:

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Answer: Option (c) is the correct answer.

Explanation:

When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.

It is given that mass is 20 kg, velocity is 5 m/s^{2}, and height is 2 m.

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             kinetic energy = \frac{1}{2}mv^{2}

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                                      = 10 kg \times 25 m^{2}/s^{2}

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Also, when child falls off the ground then she will have gravitational potential energy.

Calculate gravitational potential energy of child as follows.

            Potential energy = m × g × h

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3 0
3 years ago
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kozerog [31]
<h3>Hi!</h3>

<h3>The correct answers would be:</h3>

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8 0
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\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}

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