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Aleksandr [31]
4 years ago
11

Which factor increases the amount of water runoff?

Chemistry
1 answer:
bekas [8.4K]4 years ago
7 0

D. impermeable rocks

Explanation:

Impermeable rocks is the factor among the give choices that will increase the amount of water runoff on the surface.

Surface run-off is liquid water that flows and moves on the earth surface.

  • An impermeable rock is a rock that lacks porosity and permeability.
  • Porosity is the amount or percentage of void spaces in rock.
  • Permeability is the inter-connectivity of the pores.
  • When a rock is impermeable, it will not allow water to infiltrate.

learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

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Consider the following balanced redox reaction: 2CrO2-(aq) + 2H2O(l) + 6ClO-(aq) LaTeX: \longrightarrow⟶ 2CrO42-(aq) + 3Cl2(g) +
frutty [35]

Answer:

1. Chromium

2. Chlorine.

3. Chlorine.

4. Chromium.

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Explanation:

Hello,

In this case, the given reaction with the appropriate oxidation states turns out:

2(Cr^{+3}O^{-2}_2)^-(aq) + 2H_2O(l) + 6(Cl^{+1}O^{-2})^-(aq)\longrightarrow 2(Cr^{+6}O^{-2}_4)^{2-}(aq) + 3Cl^0_2(g) + 4OH^-(aq)

In such a way, the oxidation half-reaction is written for chromium as the reducing agent so it is oxidized from +3 to +6, nonetheless, since there are two chromiums undergoing such change, 6 electrons are being transferred as shown below:

2(Cr^{+3}O^{-2}_2)^-(aq) \longrightarrow 2(Cr^{+6}O^{-2}_4)^{2-}(aq)+6e^-

On the other hand, chlorine's reduction half-reaction as the oxidizing agent result from the transfer of 6 electrons as well from +1 to 0, nonetheless, there are 6 chlorines undergoing such change:

6(Cl^{+1}O^{-2})^-+6e^-\longrightarrow 3Cl^0_2(g)

Therefore, there are 12 electrons that are being transferred, 6 for chromium and 6 for chlorine.

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A molecule of acetone and a molecule of propyl aldehyde are both made from 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.
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Explanation:

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In the formula of propanal there is -CHO functional group at the end.

In acetone -CO- group is present in the middle that is on the second carbon.

The molecular formula is C3H6O.

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