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3 years ago

Which factor increases the amount of water runoff?

Chemistry

1 answer:

bekas [8.4K]3 years ago

7 0

D. impermeable rocks

Explanation:

Impermeable rocks is the factor among the give choices that will increase the amount of water runoff on the surface.

Surface run-off is liquid water that flows and moves on the earth surface.

An impermeable rock is a rock that lacks porosity and permeability.
Porosity is the amount or percentage of void spaces in rock.
Permeability is the inter-connectivity of the pores.
When a rock is impermeable, it will not allow water to infiltrate.

learn more:

Biogeochemical cycle brainly.com/question/3509510

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Hat is the definition for a scientific theory? A. an informed explanation that can be tested but is not widely accepted B. an ex

frosja888 [35]

Answer:

D. a scientific explanation that is agreed on by all scientists and is no longer adjusted as new evidence is found

Explanation:

Scientific theory is an explanation that has been repeatedly tested and verified in accordance with the scientific method, using accepted protocols of observation, measurement, and evaluation of results

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3 years ago

Read 2 more answers

There are over 100 elements, but only

elena-14-01-66 [18.8K]

Answer:

Symbol_Element

He_Helium

Li_Lithium

Be_Beryllium

B_Boron

C_Carbon

N_Nitrogen

O_Oxygen

F_Fluorine

Ne_Neon

Na_Sodium

Mg_Magnesium

Al_Aluminum

Si_Silicon

P_Phosphorous

S_Sulfur

Cl_Chlorine

Ar_Argon

K_Potassium

Ca_Calcium

Sc_Scandium

Ti_Titanium

V_Vanadium

Cr_Chromium

Mn_Manganese

Fe_Iron

Co_Cobalt

Ni_Nickel

Cu_Copper

Zn_Zinc

Ga_Gallium

Ge_Germanium

As_Arsenic

Se_Selenium

Br_Bromine

6 0

3 years ago

The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t

Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

$2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?$

We have :

Enthalpy changes of formation of following s:

$\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol$

$\Delta H_{f,CuO}=-157.3 kJ/mol$

$\Delta H_{f,NO_2}= 33.2 kJ/mol$

$\Delta H_{f,O_2}= 0 kJ/mol$ (standard state)

$\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]$

The equation for the enthalpy change of the given reaction is:

$\Delta H_{rxn}$ =

$=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})$

$\Delta H_{rxn}$ =

$(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)$

$\Delta H_{rxn}=424 kJ$

The enthalpy change for the given reaction is 424 kJ.

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4 years ago

What are some examples of van der waals forces?

Rudiy27

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