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tamaranim1 [39]

3 years ago

6

What is the number of electrons shared in the multiple carbon-carbon bond in one molecule of 1-pentyne?

2 answers:

Vesnalui [34]3 years ago

8 0

The correct answer for the given question above would be option A. The number of electrons shared <span> in the multiple carbon-carbon bond in one molecule of 1-pentyne is 6. -YNE is considered as a triple bond. This would mean 3 pairs of electrons of 6 electrons. Hope this answers your question. Have a great day!</span>

son4ous [18]3 years ago

7 0

<u>Answer:</u> The correct answer is Option 1.

<u>Explanation:</u>

1-pentyne is a hydrocarbon which has a triple bond present between carbon and carbon atoms. This is considered as an unsaturated hydrocarbon and an alkyne.

To form a single bond, number of electrons required are 2.

Here, triple bond is present between carbon and carbon atoms, so number of electrons required to form this bond will be $(2\times 3)=6$

Hence, the correct answer is Option 1.

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Converting the following mm Hg (torr) to standard

11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0

3 years ago

Which of the following covalent bonds is the strongest?

Basile [38]

Answer:

a) quadruple covalent bond

Explanation:

Quadruple covalent bonds are the strongest covalent bonds. The more the number of bonding pairs, the stronger the bond becomes.

A covalent bond is formed by sharing of electrons between two species.
They are usually between compound with similar electronegativities.
The number of bonds between the atom determines the bond strength.

Single < double < triple < quadruple covalent bonds.

7 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

choli [55]

Explanation:

a) $H_2SO_4$

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of S be x.

$2\times1+ x+2\times -4 =0$

$2 +x-8 = 0\\x=+6$

Oxidation state of S in $H_2SO_4$ = +6

b) $Ca(OH)_2$

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of Ca be x.

$x+2\times-2+2\times+1 =0\\x=4 -2\\x=+2$

Oxidation state of Ca in $Ca(OH)_2$ = +2

c) BrOH

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of Br be x.

$x+1\times-2+1\times+1 =+1$

Oxidation no. of Br in BrOH is +1

d) $ClNO_2$

oxidation state of Cl = -1

Oxidation state of O = -2

Let the oxidation no. of N be x.

$-1+x+2\times-2\\x = 4+1 =+5$

Oxidation state of N in $ClNO_2$ = +3

e) $TiCl_4$

oxidation state of Cl = -1

Let the oxidation no. of Ti be x.

$x+4\times -1 = 0\\x=+4$

Oxidation state of Ti in $TiCl_4$ = +4

f) NaH

Na is more electropositive than H.

Therefore, oxidation state of Na = +1

Oxidation state of H = -1

6 0

3 years ago

what is the order of: chlorine, oxygen, and carbon from greatest to least according to ionic radius?

Nataly_w [17]

Answer:

Oxgyen

Explanation:

Ok semoga membantu kamu bro

jadikan jawabban tercerdasa ya

6 0

3 years ago

How do you find pH if Distilled water is the solvent

valentinak56 [21]

There you go , This is my work i have did on that subject area

5 0

4 years ago