Explanation:
Fe²⁺ + 2e⁻ → Fe
In a reduction half, the oxidizing agent is getting reduced. Such ion is donating electrons.
In a reduction process:
- there is removal of oxygen from a specie
- addition of hydrogen to a specie
- gain of electron by an atom
- decrease in oxidation number of an atom
- decrease in number of electronegative atoms surrounding the element in changing from reactants to products.
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Volume of a rectangular block= 2.30x4.01x1.82=16.78cm3
Mass of the rectangular block= 25.71 g
Density of the block will be = 25.71/16.78=1.53 g/cm3
So the
ANSWER IS 1.53 g/cm3 density
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Answer:
Option A) oxygen
Explanation:
Oxygen gas it the electrolysis of an aqueous solution of sodium nitrate which a gas forms at anode it is called the oxygen gas
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