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Verizon [17]
3 years ago
5

Na2SO4 is dissolved in water to make 450mL of a 0.2250 M solution. What is the molar mass of Na2SO4?

Chemistry
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

mass Na2SO4 = 14.3816 g

Explanation:

sln Na2SO4:

∴ V = 450 mL

∴ <em>C </em>=<em> </em>0.2250 mol/L

∴ Mw ≡ 142.04 g/mol.....  from literature

⇒ mol Na2SO4 = (0.2250 mol/L)(0.450 L) = 0.10125 mol

⇒ mass Na2SO4 = (0.10125 mol)(142.04 g/mol) = 14.3816 g

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Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

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In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

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Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

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<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

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<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

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