two atoms have the same number of protons but different number of neutrons. what can you conclude about these masses
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Answer : The concentration of at equilibrium is, 0.244 M, 0.122 M and 1.267 M respectively.
Explanation :
The given chemical reaction is:
Initial conc. 0.439 0.317 0.877
At eqm. (0.439-x) (0.317-x) (0.877+2x)
As we are given:
The expression for equilibrium constant is:
Now put all the given values in this expression, we get:
x = 0.195 and x = 0.690
We are neglecting the value of x = 0.690 because equilibrium concentration can not be more than initial concentration.
Thus, the value of x = 0.195 M
The concentration of at equilibrium = (0.439-x) = (0.439-0.195) = 0.244 M
The concentration of at equilibrium = (0.317-x) = (0.317-0.195) = 0.122 M
The concentration of at equilibrium = (0.877+2x) = (0.877+2\times 0.195) = 1.267 M
<u>Answer:</u> The percent yield of oxygen gas is 67.53 %.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of water = 17.0 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of water produces 1 mole of oxygen gas
So, 0.944 moles of water will produce = of oxygen gas
Now, calculating the mass of oxygen gas from equation 1, we get:
Molar mass of oxygen gas = 32 g/mol
Moles of oxygen gas = 0.472 moles
Putting values in equation 1, we get:
To calculate the percentage yield of oxygen gas, we use the equation:
Experimental yield of oxygen gas = 10.2 g
Theoretical yield of oxygen gas = 15.104 g
Putting values in above equation, we get:
Hence, the percent yield of oxygen gas is 67.53 %.