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Ket [755]
3 years ago
12

Consider the function attached below

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answer:

2

Step-by-step explanation:

Hello,

x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{2f^{-1}(x)}+5\\\sqrt{2f^{-1}(x)} =x-5\\2f^{-1}(x)=(x-5)^2\\f^{-1}(x)=\dfrac{(x-5)^2}{2}

now let's replace x by 7 it comes

f^{-1}(7)=\dfrac{(7-5)^2}{2}=\dfrac{2^2}{2}=2

hope this helps

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