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3 years ago

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4^x-3=6 please help

1 answer:

SashulF [63]3 years ago

3 0

$4^{x+3}=6\ \ \ \ |\log_4\\\\\log_44^{x+3}=\log_46\ \ \ |\text{Use}\ \log_ab^n=n\log_ab\\\\(x+3)\log_44=\log_46\ \ \ \ |\text{Use}\ \log_aa=1\\\\x+3=\log_46\ \ \ |-3\\\\x=\log_46-3\ \ \ \ |\text{Use}\ b=\log_aa^b\\\\x=\log_46-\log_44^3\\\\x=\log_46-\log_464\ \ \ |\text{Use}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\x=\log_4\dfrac{6}{64}\\\\x=\log_4\dfrac{3}{32}$

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d. Given the point (-4,2), substitute this point and the slope of the line into the equation:

$y -2 = -1(x +4)$

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Give a value to "x", substitute it into this equation and solve for "y":

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