4^x-3=6 please help

Mathematics

1 answer:

SashulF [63]2 years ago

3 0

$4^{x+3}=6\ \ \ \ |\log_4\\\\\log_44^{x+3}=\log_46\ \ \ |\text{Use}\ \log_ab^n=n\log_ab\\\\(x+3)\log_44=\log_46\ \ \ \ |\text{Use}\ \log_aa=1\\\\x+3=\log_46\ \ \ |-3\\\\x=\log_46-3\ \ \ \ |\text{Use}\ b=\log_aa^b\\\\x=\log_46-\log_44^3\\\\x=\log_46-\log_464\ \ \ |\text{Use}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\x=\log_4\dfrac{6}{64}\\\\x=\log_4\dfrac{3}{32}$

You might be interested in

Someone pls help me <br><br><br> Solve for x

mezya [45]

The correct answer is X=-2.

First remove the parentheses and factor out 2.

1/2•(2-6x)-4(x+3/2)=-(x-3)+4 turns into
1/2•2(1-3x)-4(x+3/2)=-(x-3)+4.
Then distribute -4 through the parentheses,
1/2•2(1-3x)-4x-6=-(x-3)+4
Then change the sign of the x-3 to x+3,
1/2•2(1-3x)-4x-6=-x+3+4

Then reduce the numbers with the greatest common factor which is 2,
and remove unnecessary parentheses,
1-3x-4x-6=-x+7
Then calculate the differences and collect like terms,
-5-7x=-x+7

Then move the variable to the left side and change its sign, and move the constant to the right hand side and change its sign,
-7x+x=7+5
Then add and collect the like terms,
-6x=12
And finally divide both sides by -6 to get X=-2.

Whew lol

8 0

2 years ago

Read 2 more answers

Complete the recursive formula of the geometric sequence 16\,,\,3.2\,,\,0.64\,,\,0.128,...16,3.2,0.64,0.128,

Nastasia [14]

Answer:

$a_{n+1}=0.2a_n$ for all n>0, $a_1=16$