Answer:
5.85 moles of carbon dioxide are created.
Explanation:
The balanced reaction is:
CaCO₃ → CaO + CO₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CaCO₃: 1 mole
- CaO: 1 mole
- CO₂: 1 mole
Then you can apply the following rule of three: if by stoichiometry 1 mole of CaCO₃ produces 1 mole of CO₂, 5.85 moles of CaCO₃ will produce how many moles of CO₂?

moles of CO₂= 5.85
<u><em>5.85 moles of carbon dioxide are created.</em></u>
Answer:
The world’s oceans are so big we thought for a long time that there was nothing humans could do to hurt them. Now we’re facing an imminent and global collapse of our fisheries, projected to happen as early as 2048, thanks to overfishing, wasteful fishing practices and massive overconsumption. But, there are a few key tried-and-tested solutions to overfishing that have been successfully implemented around the world. The trick is to scale these solutions up to a global scale, encouraging countries that have originally been resistant to helping and get them onboard, and supporting countries that don’t have the means to update their fishing policies themselves.
Hope it will help you
Answer:
I believe it is B
Explanation:
I am on this lesson too :)
Iodine value is a measure of the degree of unsaturation in fats and oils. It is essentially the number of grams of iodine consumed by 100 g of fat. If the iodine number is in the range of 0-70 then it is a fat, any value above 70 is considered an oil.
Formula:
Iodine number = (ml of 0.1 N Thiosulphate blank- ml of 0.1N thiosulphate test) * 12.7 *100/1000* wt of sample
vol of thiosulphate required to titrate test sample (given oil) = 1 ml
wt of sample = 0.2 g
Information on the volume of thiosulphate required to titrate the blank solution is essential for calculation.
Iodine number = (X-1.0) * 12.7 * 100/1000* 0.2 = (X-1.0)*6.35
It would make the current slowly fade away. or be nothing/low