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Ray Of Light [21]
3 years ago
15

How many moles of Fe2O3 are in 203 g of the compound?

Chemistry
1 answer:
ruslelena [56]3 years ago
6 0
The equation is :
moles=mass/molar mass
so, the mass is 203 and molar mass is 159.69 
You divide the 203 by 156.69 as the equation shows
so the moles is 1.27 mol. 
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Given the chemical equation: Fe2O3 + 3CO --&gt; 2Fe + 3CO2
lapo4ka [179]

Answer:

The answer to your question is 160 g of Fe₂O₃  

Explanation:

Data

mass of Fe = 112 g

mass of CO = in excess

mass of Fe₂O₃ = ?

Balanced chemical reaction

                Fe₂O₃  +  3CO  ⇒  2Fe  +  3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and Fe

Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g

atomic mass of Fe = 56

2.- Use proportions to calculate the mass of Fe₂O₃ needed

                160 g of Fe₂O₃ ------------------- 2(56) g of Fe

                 x     g of Fe₂O₃ ------------------ 112 g of Fe

                 x = (112 x 160) / 2(56)

                 x = 17920/112

                 x = 160 g of Fe₂O₃          

6 0
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