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3 years ago

Expand the expression 1/2 (3+4t-10)

Mathematics

1 answer:

Alex73 [517]3 years ago

7 0

Answer:3/2 + t - 5

Step-by-step explanation:

1/2(3+4t-10)

Open brackets

3/2 + 4t/2 - 10/2

3/2 + t - 5

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18. The desired density of the shaved ice is 0.697 g/cm3, and the cost, per kilogram, of ice is $3,83. Determine

Ostrovityanka [42]

The cost of the ice needed to make 50 snow cones is $54.50.

The first step is to determine the volume of the snow cone.

Volume of the snow cone =volume of a cone + volume of the hemisphere

Volume of the cone = 1/3πr²h

1/3 x 3.14 x 10.2 x (8.3/2)² = 183.87 cm³

Volume of the hemisphere = 2/3πr³

2/3 x 3.14 x (8.3 / 2)³ = 224.43 cm³

Total volume = 224.43 cm³ + 183.87 cm³ = 408.30 cm³

Volume of 50 snow cones = 408.30 cm³ x 50 = 20,414.82

Total grams of ice needed = density x volume

0.697 x 20,414.82 = 14,229.13 grams

Convert gram to 1kg

1kg = 1000g

= 14,229.13 grams / 1000 = 14.23kg

Cost of the ice = 14.13 x 3.83 = $54.50

Please find attached the image of the snow cone. To learn more about the volume of a cone, please check: brainly.com/question/13705125

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8 0

2 years ago

Which is the graph of 3y-5x>-6

FrozenT [24]

the answer is ....... D

7 0

3 years ago

Suppose that the profit (in hundreds of dollars) of a certain firm is approximated by:

Amiraneli [1.4K]

Answer:

Step-by-step explanation:.

Given the profit (in hundreds of dollars) of a certain firm is approximated by:

P(x,y) = 1500 +36x - 1.5x^2 + 120y - 2y^2 where

x is the cost of a unit of labor

y is the cost of a unit of goods.

The maximum value of x and y occurs when dP/dx = 0 and dP/dy = 0

dP/dx is the differential of the function with respect to x taking y as a constant

dP/dy is the differential of the function with respect to y taking x as a constant

dP/dx = 0+36-2(1.5)x^{2-1}+0-0

dP/dx = 36-3x

If dP/dx = 0

36-3x = 0

36-3x-36 = 0-36

-3x = -36

x = -36/-3

x = 12

Similarly;

dP/dy = 0+0-0+120-2(2)y^{2-1}

dP/dy = 120-4y

Since dP/dy = 0

120-4y = 0

Subtract 120 from both sides

120-4y-120 = 0-120

-4y = -120

y = -120/-4

y = 30

Hence the values of x and y that maximize the profit are 12 and 30 respectively.

To find the maximum profit, we will substitute x = 12 and y = 30 into the given function

P(x,y) = 1500 +36x - 1.5x^2 + 120y - 2y^2

P(12,60) = 1500 +36(12) - 1.5(12)^2 + 120(30) - 2(30)^2

P(12,60) = 1500 +36(12) - 1.5(144) + 120(30) - 2(900)

P(12,60) = 1500 + 432 - 216 + 3600 - 1800

P(12,60) = 1932-216+1800

P(12,60) = 3,516

Since the profit is in hundreds if dollars,

P(12,60) = 3516×100

P(12,60) = $351,600

Hence the maximum profit is $351,600

8 0

3 years ago

The following points for a function are graphed in the coordinate plane: (1, 2), (3, 8), (4, 11), and (6, 17).

aleksley [76]

Answer: y=2x
I upload I picture of showing my work. Hope this help you.

4 0

3 years ago

3x(x-2) = 0<br> in standard form and its roots

slava [35]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

3x(x−2)=0

Step 1: Simplify both sides of the equation.

3×2−6x=0

For this equation: a=3, b=-6, c=0

3×2+(−6x)+0=0

Step 2: Use quadratic formula with a=3, b=-6, c=0.

$x=\frac{-b ±\sqrt{b^2-4ac} }{2a}$

x=2 or x=0

hope it helps other wise I am sorry

6 0

3 years ago