Answer: question 1 is b I believe
Explanation:
every action has an opposite reaction
Answer:
T = 0.00889 N*m
Explanation:
Given the initial speed
Vo = 9.0rev/s.
V = 65 rev/10s
V = 6.5 rev/s.
V = Vo + a*t
Solve to acceleration knowing the initial velocity and the velocity at 10 s
6.5 rev/s - 9 rev/s = a*10s
a = -0.25 rev/s^2.
Now the solve the time at stop time so V=0
V = Vo + a*t
0 = 9.0 - 0.25 rev/s *t,
t = 36 s The Stopping time.
36s - 10s = 26s
The torque can be find using the acceleration using the equation
T = I*a
I = 1/2*m*r^2
I = 1/2*0.725kg*(0.315m)^2= 0.0359kg*m^2
T = 0.0359kg*m^2*-0.25rev/s^2
T = 0.00889 N*m
Quisiera ayudarte pero no puedo apenas voy a pasar a secundaria :(
Answer:
Explanation:
First of all we shall find out net electric field at q₃ due to both of the remaining charges .
electric field due to charge Q = k Q / r² where k = 9 x 10⁹ Q is amount of charge and r is distance of point
electric field due to charge 105 x 10⁻⁶ C
= 9 x 10⁹ x 105 x 10⁻⁶ / .95²
= 1.047 x 10⁶ N/C .
It will act away from q₂
electric field due to charge 53 x 10⁻⁶ C
= 9 x 10⁹ x 53 x 10⁻⁶ /( .5+.95)²
= 0.227 x 10⁶ N/C .
It will act towards q₁
These fields are in opposite direction so
net field E = 0.82 x 10⁶ N/C.
It will act away from q₂ .
Force on q₃ due to net field
= q₃ E
= 88 x 10⁻⁶ x 0.82 x 10⁶
= 72.16 N
The direction of this field will be towards q₂ because force on negative charge in a field is always in a direction opposite to the direction of the field.
Answer:
a) FB = 260 [N]
b) FT = 230 [N]
Explanation:
In order to solve this problem we must use a static analysis, since Globe does not move. For a better understanding in solving this problem, a free body diagram with the forces acting on the globe is attached.
The buoyant force acts upward as it causes the balloon to tend to float, the weight of the balloon tends to lower the balloon and the downward tension force does not allow the balloon to float
The buoyant force is defined by the following equation:
FB = Ro*V*g
where:
FB = Buoyant force [N]
Ro = density of the air = 1.3 [kg/m^3]
V = volume of the balloon = 20 [m^3]
g = gravity acceleration = 10 [m/s^2]
FB = 1.3*20*10 = 260 [N]
Now we do a sum of forces equal to zero in the y-axis
FB - 30 - FT = 0
260 - 30 = FT
FT = 230 [N]
