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mr Goodwill [35]
2 years ago
7

The fine horizontal scratches etched onto a bullet after it has been fired are called?

Physics
1 answer:
GalinKa [24]2 years ago
4 0

The fine horizontal scratches etched onto a bullet after it has been fired are called Striations.

<h3>What is Striations?</h3>
  • Striations are the minute differences in the curve of the bullet's surface. The bullet and the gun barrel are the harder and softer materials, respectively, in firearms evidence.
  • The striations left on the fired bullet are used as a comparison by firearm examiners.
  • When a gun is discharged, the bullet blasts down the barrel where it strikes ridges and grooves, spinning and improving shot accuracy.
  • These ridges cause striations in the bullet's soft metal by digging into it.
  • An examiner analyses these distinctive markings to verify whether a given bullet was shot from a specific firearm.
  • A barrel will produce individual markings in addition to a bullet's land and groove impressions as the projectile passes through.

Learn more about Bullet here:

brainly.com/question/6669700

#SPJ4

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Answer:Magnetic fields are invisible, at least usually. But scientists from NASA's Space Sciences Laboratory have made them visible as "animated photographs," using sound-controlled CGI and 3D compositing.

Explanation:

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3 years ago
A concave lens has a focal length of 20 cm. A real object is 30 cm from the lens. Where is the image? What is the magnification?
Pani-rosa [81]

Answer:

12 cm and 0.4

Explanation:

f = - 20 cm, u = - 30 cm

Let v be the position of image and m be the magnification.

Use lens equation

1 / f = 1 / v - 1 / u

- 1 / 20 = 1 / v + 1 / 30

1 / v = - 5 / 60

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In the heat equation what does Q represent
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6 0
3 years ago
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A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. C
lozanna [386]

Hello!

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

We have the following data:

* velocity (in mph)

(V1) = 35.0 mph

(V2) = 40.0 mph

(V3) = 50.0 mph

* weights for the time (in hours)

(T1) = 1.00 hour

(T2) = 0.0500 hour

(T3) = 2.00 hours

We apply the data to the weighted average formula to find the average speed, let us see:

Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}

Weight\:Average = \dfrac{35.0*1.00+40.0*0.0500+50.0*2.00}{1.00+0.0500+2.00}

Weight\:Average = \dfrac{35+2+100}{3.05}

Weight\:Average = \dfrac{137}{3.05}

Weight\:Average = 44.91803279...

\boxed{\boxed{Weight\:Average = 44.92\:mph}}\Longleftarrow(Average\:Speed)\:\:\:\:\:\:\bf\purple{\checkmark}

Answer:

The Average Speed is approximately 44.92 mph

_______________________

\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

7 0
3 years ago
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θ = angle of the incline surface from the horizontal surface = 25⁰

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the free body diagram showing the forces acting on the person is given as


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