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mr Goodwill [35]
2 years ago
7

The fine horizontal scratches etched onto a bullet after it has been fired are called?

Physics
1 answer:
GalinKa [24]2 years ago
4 0

The fine horizontal scratches etched onto a bullet after it has been fired are called Striations.

<h3>What is Striations?</h3>
  • Striations are the minute differences in the curve of the bullet's surface. The bullet and the gun barrel are the harder and softer materials, respectively, in firearms evidence.
  • The striations left on the fired bullet are used as a comparison by firearm examiners.
  • When a gun is discharged, the bullet blasts down the barrel where it strikes ridges and grooves, spinning and improving shot accuracy.
  • These ridges cause striations in the bullet's soft metal by digging into it.
  • An examiner analyses these distinctive markings to verify whether a given bullet was shot from a specific firearm.
  • A barrel will produce individual markings in addition to a bullet's land and groove impressions as the projectile passes through.

Learn more about Bullet here:

brainly.com/question/6669700

#SPJ4

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An airplane is flying in a horizontal circle at a speed of 480 km/h. If its wings are tilted 40° to the horizontal, what is the
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Answer:

r = 2161.9 m

Explanation:

Aerodynamic lift(L) is perpendicular to the wing, which is tilted 40 degrees to the horizontal.

Since the plane is moving in a horizontal circle, the vertical component of the lift must cancel the weight W of the airplane, but the horizontal component is the centripetal force that keeps it in a circle.

L is perpendicular to wing at angle θ with respect to horizontal

Thus,

Vertical component of lift is:

L cosθ = W = mg

Thus, m = L cosθ / g - - - - (eq1)

Horizontal component of lift is:

L sinθ = centripetal force = mv² / r - - - - (eq2)

Combining equations 1 and 2,we have;

L sinθ = (L cosθ / g)(v² / r)

L cancels out on both sides to give;

tanθ = v²/ rg

r = v² / (g tanθ)

We are given;

velocity; v = 480 km/hr = 480 x 10/36 = 133.33 m/s

r = 133.33²/[(9.8) tan(40)] = 2161.9 m

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