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melisa1 [442]
2 years ago
6

La pregunta dice asi: de las acciones politicas que pone como ejemplo norberto bobbio, elija una y expliquela

Physics
1 answer:
Ksivusya [100]2 years ago
5 0

Quisiera ayudarte pero no puedo apenas voy a pasar a secundaria :(

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The weight of an object is the product of its mass, mmm, and the acceleration of gravity, ggg (where g=9.8 m/s2g=9.8 m/s2). If a
Andre45 [30]

Answer:

Weight of the object will be 98 N

Explanation:

We have given mass of the object m = 10 kg

Acceleration due to gravity g=9.8m/sec^2

We have to find the weight of the object

Weight of the object is dependent on mass and acceleration due to gravity, it is the product of mass and acceleration due to gravity

So weight of the object W = mass × acceleration due to gravity

So W=10\times 9.8=98N

So weight of the object will be 98 N

4 0
3 years ago
A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to
777dan777 [17]

Explanation:

∆x=300 m×2

∆t=1.5 s

v=∆x/∆t → v=2×300/1.5 = 400 m/s

6 0
2 years ago
Work of 5 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (i
densk [106]

Answer:

Explanation:

Given that,

5J work is done by stretching a spring

e = 19cm = 0.19m

Assuming the spring is ideal, then we can apply Hooke's law

F = kx

To calculate k, we can apply the Workdone by a spring formula

W=∫F.dx

Since F=kx

W = ∫kx dx from x = 0 to x = 0.19

W = ½kx² from x = 0 to x = 0.19

W = ½k (0.19²-0²)

5 = ½k(0.0361-0)

5×2 = 0.0361k

Then, k = 10/0.0361

k = 277.008 N/m

The spring constant is 277.008N/m

Then, applying Hooke's law to find the applied force

F = kx

F = 277.008 × 0.19

F = 52.63 N

The applied force is 52.63N

6 0
3 years ago
In an extrasolar planetary system containing a single planet, the parent star is measured to move about its center of mass every
Mademuasel [1]

Answer:

Orbital Time Period is 24 years

Explanation:

This can be explained by the definition of time period.

Time period can be defined as the time taken by an object to complete one cycle, here, time taken to complete one revolution.

Also, we know that an extra solar planet which is also called as an exo planet is that planet which is outside our solar system and orbits any star other than our sun. The system in consideration is extra solar system with a single planet.

Therefore, the time taken by the parent star to move about its mass center is the orbital time period that is 24 years.

4 0
3 years ago
Cells a and f shows an early and late stage of the same phase of mitosis . what phase is it?
Lerok [7]
Fun fhjzsh going chichi. Gok
3 0
3 years ago
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