Answer:
Explanation:
First of all we shall find out net electric field at q₃ due to both of the remaining charges .
electric field due to charge Q = k Q / r² where k = 9 x 10⁹ Q is amount of charge and r is distance of point
electric field due to charge 105 x 10⁻⁶ C
= 9 x 10⁹ x 105 x 10⁻⁶ / .95²
= 1.047 x 10⁶ N/C .
It will act away from q₂
electric field due to charge 53 x 10⁻⁶ C
= 9 x 10⁹ x 53 x 10⁻⁶ /( .5+.95)²
= 0.227 x 10⁶ N/C .
It will act towards q₁
These fields are in opposite direction so
net field E = 0.82 x 10⁶ N/C.
It will act away from q₂ .
Force on q₃ due to net field
= q₃ E
= 88 x 10⁻⁶ x 0.82 x 10⁶
= 72.16 N
The direction of this field will be towards q₂ because force on negative charge in a field is always in a direction opposite to the direction of the field.
