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2 years ago

According to Newton's first law, if an object is changing direction, what must be happening?

Physics

1 answer:

murzikaleks [220]2 years ago

6 0

D. Unbalanced forces are acting on it.

hope this helped

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What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave

Firlakuza [10]

Answer:

thinnest soap film is 206.76 nm

Explanation:

Given data

wavelength = 550 nm

index of refraction n = 1.33

to find out

What is the thinnest soap film

solution

we have wavelength λ = 550 nm

that is λ = 550 × $10^{-9}$ m

and n = 1.3

we will find the thickness of soap film as given by formula that is

thickness = λ/2n

thickness = 550 × $10^{-9}$ / 2(1.33)

thickness = 206.76 × $10^{-9}$ m

thinnest soap film is 206.76 nm

7 0

2 years ago

WHICH SHOULD NOT BE PART OF SCIENTIFIC INQUIRY

umka21 [38]

Answer:

Not collecting the info

Explanation:

5 0

2 years ago

Some drops a ball off of the top of a 125-m-tall building. In this prob-lem, you will be solving for the time it takes the ball

Nimfa-mama [501]

Answer:

t = 5.05 s

Explanation:

This is a kinetic problem.

a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m

b) in this system the equations of motion are

y = v₀ t + ½ g t²

where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth

e) y = 0 + ½ g t²

t = √ (2y / g)

t = √(2 125 / 9.8)

t = 5.05 s

6 0

2 years ago

What is the weight of a dust particle

Alexandra [31]

Answer:

The mass of a dust particle is 7.53 x 10^-10 kg. (Hope it helped.)

Explanation:

3 0

3 years ago

The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various

Schach [20]

Answer:

$q = -461532.5 \ C$

Explanation:

From the question we are told that

The electric filed is $E = 102 \ N/C$

Generally according to Gauss law

=> $E A = \frac{q}{\epsilon_o }$

Given that the electric field is pointing downward , the equation become

$- E A = \frac{q}{\epsilon_o }$

Here $q$ is the excess charge on the surface of the earth

$A$ is the surface area of the of the earth which is mathematically represented as

$A = 4\pi r^2$

Where r is the radius of the earth which has a value $r = 6.3781*10^6 m$

substituting values

$A = 4 * 3.142 * (6.3781*10^6 \ m)^2$

$A =5.1128 *10^{14} \ m^2$

$q = -E * A * \epsilon _o$

Here $\epsilon_o$ s the permitivity of free space with value

$\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

substituting values

$q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}$

$q = -461532.5 \ C$

6 0

3 years ago