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Alenkinab [10]
3 years ago
15

Winds that blow from the north and south poles

Physics
1 answer:
Gennadij [26K]3 years ago
8 0
Winds that blow from the north and south poles would be called k<span>atabatic winds. I'm not sure if I spelled that right, but that's the answer I hope.</span>
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Math phys can i have help 7-10
Vladimir79 [104]

Answer:

007. 4. 124.091

008. 9. 0.232679738562091

009. 1. 66.8457608738846

010. 3. 14.2 N

Explanation:

007. Speed of a wave is the product of its wavelength and it frequency.

v = λ f

For a given velocity, the minimum frequency occurs at the maximum wavelength.

For a standing wave, the distance between the nodes (fixed points that don't oscillate) is a multiple of half the wavelength.

L = k/2 λ

The wavelength is a maximum at k=1 (also known as the first harmonic).

L = 1/2 λ

λ = 2L

Substituting and solving for f:

v = 2L f

f = v / (2L)

f = 546 m/s / (2 × 2.2 m)

f = 124.091 Hz

008. The sound travels from the dolphin to the ocean floor, then back to the dolphin.  So it travels a total distance of 2 × 178 m = 356 m.  At a speed of 1530 m/s, the time it takes for the sound to travel this distance is:

t = d / v

t = 356 m / 1530 m/s

t = 0.232679738562091 s

009. Sound intensity in decibels is:

I(db) = 10 log(I / I₀)

where I is the sound intensity (W/m²) and I₀ is the threshold of hearing.

We know that the sound intensity I is proportional to the number of cars per minute.  If we say n is the number of cars per minute, and k is the constant of proportionality, then:

I(db) = 10 log(kn / I₀)

When n = 132, I = 73.

73 = 10 log(132k / I₀)

7.3 = log(132k / I₀)

10^7.3 = 132k / I₀

k / I₀ = (10^7.3) / 132

k / I₀ = 151156.236

So the equation for intensity in decibels is:

I(db) = 10 log(151156.236 n)

When n = 32:

I(db) = 10 log(151156.236 × 32)

I(db) = 66.8457608738846

010. For a vibrating string, the tension is:

T = v² m/L

where v is the speed and m/L is the mass per length of the string.

When v = 18.6, T = 6.43.

6.43 = (18.6)² m/L

m/L = 0.01859

So the equation is:

T = 0.01859 v²

When v = 27.6:

T = 0.01859 (27.6)²

T = 14.2 N

4 0
3 years ago
The answer using the graphical method and analytical method of vector addition will always be.
Alex17521 [72]

The answer using the graphical method and analytical method of vector addition will always be

C. Same

Analytic method means adding vectors (x₁,y₁) and (x₂,y₂) give (x₁+x₂,y₁+y₂)

Example: Addition of (2,3) and (1,1) gives (3,4)

Solving it graphically will also give (3,4)

4 0
4 years ago
A bullet with a mass m b = 11.9 mb=11.9 g is fired into a block of wood at velocity v b = 261 m/s. vb=261 m/s. The block is atta
fredd [130]

Answer:

0.372 kg

Explanation:

The collision between the bullet and the block is inelastic, so only the total momentum of the system is conserved. So we can write:

mu=(M+m)v (1)

where

m=11.9 g = 11.9\cdot 10^{-3}kg is the mass of the bullet

u=261 m/s is the initial velocity of the bullet

M is the mass of the block

v is the velocity at which the bullet and the block travels after the collision

We also know that the block is attached to a spring, and that the surface over which the block slides after the collision is frictionless. This means that the energy is conserved: so, the total kinetic energy of the block+bullet system just after the collision will entirely convert into elastic potential energy of the spring when the system comes to rest. So we can write

\frac{1}{2}(M+m)v^2 = \frac{1}{2}kx^2 (2)

where

k = 205 N/m is the spring constant

x = 35.0 cm = 0.35 m is the compression of the spring

From eq(1) we get

v=\frac{mu}{M+m}

And substituting into eq(2), we can solve to find the mass of the block:

(M+m) \frac{(mu)^2}{(M+m)^2}=kx^2\\\frac{(mu)^2}{M+m}=kx^2\\M+m=\frac{(mu)^2}{kx^2}\\M=\frac{(mu)^2}{kx^2}-m=\frac{(11.9\cdot 10^{-3}\cdot 261)^2}{(205)(0.35)^2}-11.9\cdot 10^{-3}=0.372 kg

4 0
3 years ago
What are you calculating when forces are added together
ra1l [238]

Answer:A

Explanation:

8 0
3 years ago
Static cling makes your clothes stick together. what causes this to happen? 1. external forces to the clothes 2. forces of natur
djyliett [7]
This phenomenon is as a result of static friction created by the tumbling clothes. Static friction results from the rubbing together of two or mores objects or body and electrons are stripped from one surface of the clothes more than the other. This creates an electrostatic force of attractions between the positive charges on one cloth and the negative charges on the other cloth.(unlike charges attract).
5 0
3 years ago
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