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Alenkinab [10]
3 years ago
15

Winds that blow from the north and south poles

Physics
1 answer:
Gennadij [26K]3 years ago
8 0
Winds that blow from the north and south poles would be called k<span>atabatic winds. I'm not sure if I spelled that right, but that's the answer I hope.</span>
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A law of motion that states that an object at rest stays at rest and one in motion stays
adoni [48]

Answer:

that is the first law of motion or newtons first law of motion

6 0
3 years ago
Find the kinetic energy of a 0.1-kilogram toy truck moving at the speed of 1.1 meters per second.
Viktor [21]

Answer:

0.061 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the toy truck in the problem, we have

m = 0.1 kg is its mass

v = 1.1 m/s is its speed

Putting the numbers into the equation, we find

K=\frac{1}{2}(0.1 kg)(1.1 m/s)^2=0.061 J

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4 years ago
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A 2kg 2 kg object is moving in along the x x -axis under a single conservative force. When the object is at position x=0 x = 0 ,
Luden [163]

Answer:

The particle comes to rest before reaching the position x=4m.

Explanation:

When the object is at x=0m, all of its energy is kinetic energy. Using the equation for kinetic energy yields KE=1/2mv^2=(12)(2)(3)^2=9J. Using the given equation for potential energy when the object is at x=4m yields U=4x^2=4(4)^2=64J. Since the system only has 9J of energy, the object comes to rest before reaching x=4m.

7 0
3 years ago
Shelley is in an elevator that is traveling downward and slowing down at a rate of
liraira [26]

Answer:

N = 648.55[N]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F =  Forces applied [N]

m = mass = 73.2 [kg]

a = acceleration = 0.950 [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

-m*g + N = -m*a\\

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force (or weight) measured by the scale = 83.4 [N]

Now replacing:

-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N]

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

8 0
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