All categories

1 year ago

I don’t not get anything to do with this question

Physics

2 answers:

Scorpion4ik [409]1 year ago

7 0

Answer:

Explanation:

Mechanical energy = kintetic energy + grav potential energy

ME = KE + GPE <==== re-arrange

GPE = ME - KE <==== KE = 1/2 m v^2

krek1111 [17]1 year ago

5 0

Answer:

The correct answer is C

Explanation:

hope it will help you

You might be interested in

Convert 500ml to how many liters

Mashutka [201]

500 ml = 0.5 liters. that's what i'm getting

hope it helps

7 0

2 years ago

Read 2 more answers

Any two application of gravity

Brrunno [24]

Answer:

Well the definition of an application is the act of putting to a special use or purpose so lam assuming that you want specific uses that scientists make of gravity in their work.

Well our first application has helped us to send satellites around the solar system with what Nasa calls gravity assist. Using a particular planets gravity to slingshot a satellite to another destination. Look it up.

The next application much simpler but here on Earth. There are many hydro-electric power stations in use all over the world. Water is stored at a high level and released falling 100s of metres to a turbine where it generates electricity.

Hope that helps.

Explanation:

5 0

2 years ago

A 125kg bumper car going 12m/s hits a 235kg bumper car going -13m/s.if the first car bounces back at -12.5m/s what is the veloci

vovikov84 [41]

According to the law of conservation of momentum:

$m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'$

m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision

Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.

m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?

$m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'$
$(125kg)(12m/s)+(235kg)(-13m/s)=(125kg)(-12.5m/s)+(235kg)(v_{2}'$
$1,500kg.m/s+(-3055kg.m/s)=(-1562.5kg.m/s)+(235kg)(v_{2}')$
$-1,555kg.m/s=(-1562.5kg.m/s)+(235kg)(v_{2}')$

Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.

$-1,555kg.m/s + 1562.5kg.m/s=(235kg)(v_{2}')$
$7.5kg.m/s=(235kg)(v_{2}')$
$(7.5kg.m/s)/(235kg)=(v_{2}')$
$0.03m/s=(v_{2}')$

The velocity of the 2nd car after the collision is 0.03m/s.

5 0

3 years ago

The diameter of the moon is a little less than the distance across the United States. Please select the best answer from the cho

dlinn [17]

Answer:

true

Explanation:

The diameter of the Moon is 3474 km. The distance across the United States, from Florida to Washington, is 4509.382 km.

6 0

2 years ago

Read 2 more answers

What is equal to the kinetic energy of a car with a mass of 0.5t (tonne) if it travels evenly at 70 km/h?

Aleonysh [2.5K]

Formula for kinetic energy is 1/2mv^2 so that answer should most probably be 94521.6J

5 0

2 years ago