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bogdanovich [222]
2 years ago
13

I don’t not get anything to do with this question

Physics
2 answers:
Scorpion4ik [409]2 years ago
7 0

Answer:

C

Explanation:

Mechanical energy =   kintetic energy + grav potential energy

ME                            = KE    + GPE           <====  re-arrange

GPE = ME - KE               <==== KE = 1/2 m v^2

<u>GPE = ME - 1/2 mv^2 </u>

krek1111 [17]2 years ago
5 0

Answer:

The correct answer is C

Explanation:

hope it will help you

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Two cars start from rest at a red stop light. When the light turns green, both cars accelerate forward. The blue car accelerates
marta [7]
First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used are:

For constant acceleration:
a = v,final - v,initial /t
d = v,initial*t + 1/2*at²

For constant velocity:
d = constant velocity*time

The solutions is as follows:

   a = v,final - v,initial /t
  3.8 = (v₁ - 0)/4.6 s
  v₁ = 17.48 m/s

    Total distance = d1 + d2 + d3
    d1 = d = v,initial*t + 1/2*at²
    d2 = constant velocity*time
    
   Total distance =  0*(4.6) + 1/2*(3.8)(4.6)² + (17.48)(9.2) + d3= 257.71
   d3 = 56.69 m

3 0
3 years ago
What is the weight of a spring balance when the point is 30​
andrezito [222]

Answer:

A 30 lb weight is attached to the end of a spring. The spring is stretched 6 in. Find the equation of motion if the weight is released from rest a point 3 inches above equilibrium position 。x(,) =-2 sin(81) 32 x(t) =-32 cos(80 O x(r) =-icos(81)

Explanation:

8 0
2 years ago
How does the gravitational force between two objects change if the distance
Anestetic [448]

Answer:

The Gravitational Force is reduced 4 times

Explanation:

The equation of Gravitational force follows:

F = (G*m1*m2)/r^2

Assume that G*m1*m2 = 1 and r = 1:

F = 1/1^2 = 1 N

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F = 1/2^2 = 1/4 N

So doubling the distance reduces the force 4 times.

7 0
3 years ago
Im bad at work problems can any one help with this problem ?
lyudmila [28]
We will put the number of trips in the first column, the miles driven in the second column and gallons of fuel used in the third column.

8    7,680    1,010
7    9,940    1,330
12  14,640  1,790
12  13,920  2,050
4 0
3 years ago
10) If the mass 2m, the left mass
Romashka-Z-Leto [24]

Answer:

F = \frac{-Gm_{1}m_{2} }{r^{2} }.

Explanation:

Gravitational force between two objects of masses m_{1},  m_{2} kept at a distance r is given by the formula

F = \frac{-Gm_{1}m_{2} }{r^{2} }

Here ,m_{1} = 2m

         m_{2} = \frac{m}{2}

         

Thus , F = \frac{-G.2m.\frac{m}{2} }{r^{2} }

          F = \frac{-Gm_{1}m_{2} }{r^{2} }.

7 0
3 years ago
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