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Tcecarenko [31]
3 years ago
15

A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on

the object (in m/s^2)?
Physics
1 answer:
aliya0001 [1]3 years ago
5 0

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

                       F = ma

solve for a

                       a = \frac{F}{m}

Substitution

                       a = \frac{100}{400}

Simplification and result

                              a = 0.25 m/s²

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Answer :

(1) The density of asphalt is, 1200kg/m^3

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

<u>Part 1 :</u>

As we are given:

Mass of block = 90 kg

Volume of block = 0.075m^3

Formula used :

\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}

Now put all the given values in this formula, we get:

\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3

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<u>Part 2(a) :</u>

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

<u>Part 2(b) :</u>

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}

2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}

\text{Mass of aluminium}=15.59kg

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

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