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Tcecarenko [31]

2 years ago

15

A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on

the object (in m/s^2)?

1 answer:

aliya0001 [1]2 years ago

5 0

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

F = ma

solve for a

a = $\frac{F}{m}$

Substitution

$a = \frac{100}{400}$

Simplification and result

a = 0.25 m/s²

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When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s

Aleksandr-060686 [28]

Answer:

a

$k = 457333.3 N/m$

b

$x_a =0.09\ m$

Explanation:

From the question we are told that

The total mass of three people is $M = 2.00*10^{2} \ kg$

The mass of the car is $m_c = 1.200 *10^{3} \ kg$

The compression of the car spring is $x = 3 \ cm = 0.03 \ m$

Generally the spring constant is mathematically represented as

$k = \frac{F}{x}$

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as

=> $F = (M +m_c) *g$

=> $F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8$

=> $F = 13720 \ N$

So

$k = \frac{13720}{0.03}$

=> $k = 457333.3 N/m$

Generally if the mass which the car is loaded with is $m = 3.00*10^{2} \ kg$

Then the force experienced by the spring is

=> $F_a = (m +m_c) *g$

=> $F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8$

=> $F_a = 41160 \ N$

Generally from the above formula the compression is

$x_a = \frac{F_a}{k}$

=> $x_a = \frac{41160}{457333.3}$

=> $x_a =0.09\ m$

3 0

2 years ago

Which statement is the best interpretation of the ray diagram shown?

Stells [14]

Answer: a convex lens forms a larger virtual image

Explanation: i just took the quiz

3 0

2 years ago

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An object is moving on a horizontal frictionless surface. if the net force applied to the object in the direction of motion is d

sukhopar [10]

Answer:

doubled

Explanation:

F=ma1----------(1)

2F = ma2-------(2)

Divide 2nd equation by 1st one

we get a1×2=a2

5 0

1 year ago

Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou

Mariulka [41]

Answer:

w = 1.976 rpm

Explanation:

For simulate the gravity we will use the centripetal aceleration $a_c$ , so:

$a_c = w^2r$

where w is the angular aceleration and r the radius.

We know by the question that:

r = 60.5m

$a_c$ = 2.6m/s2

So, Replacing the data, and solving for w, we get:

$2.6m/s = w^2(60.5m)$

W = 0.207 rad/s

Finally we change the angular velocity from rad/s to rpm as:

W = 0.207 rad/s = 0.207*60/(2 $\pi$ )= 1.976 rpm

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2 years ago

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2 years ago