Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.
So we have 1/2 MV^2 = MGH
V^2 = 2GH
V = âš2GH
V = âš( 2 * 9.8 * 325)
V = âš 6370
V = 79.81 m/s
I am not entirely sure but i believe the answer is C scupture
The first one is the light bends sheikh is known as refraction
Responder:
Fy = 2474,8737
Fx = 2474,8737
Explicación:
Dado que :
Dado:
Fuerza, F = 3500 N
Ángulo formado con la horizontal, θ, = 45 °
Los componentes de una fuerza se pueden descomponer en componentes verticales y horizontales.
El componente vertical Fy; y
El componente horizontal Fx
Fy = Fuerza * sinθ
Fy = 3500 * sin45 °
Fy = 2474,8737
El componente horizontal:
Fx = Fuerza * cosθ
Fy = 3500 * cos45 °
Fy = 2474,8737
Answer:
fr = ½ m v₀²/x
Explanation:
This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.
The best way to solve this exercise is to use the energy work theorem
W = ΔK
Where work is defined as the product of force by distance
W = fr x cos 180
The angle is because the friction force opposes the movement
Δk =
–K₀
ΔK = 0 - ½ m v₀²
We substitute
- fr x = - ½ m v₀²
fr = ½ m v₀²/x
