Answer:
a. -5,4
b. 28
Explanation:
(see how to solve in pic)
I think it’s C I’m sorry if I’m wrong.
You got this I believe in you!
force of friction on the cart is given as

here we also know the reaction force due to surface

so we can say reaction force is given as




now by force balance we will say



also we know that



now minimum force required to set this into motion

here we know that



So it will require 259 N minimum force to move it
Answer:
Apply the following formulae horizontally And get A value for time
Remember horizontal acceleration is zero

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

Yes because if not people wouldn't understand how did you calculate electric field strength.