Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
No,
To emit light an electron has to jump down to a lower energy level but in an electron is unable to go any lower in ground state.
The correct answer would be B.
Answer:
Time = 0.55 s
Height = 8.3 m
Explanation:
The ball is dropped and therefore has an initial velocity of 0. Its acceleration, g, is directed downward in the same direction as its displacement, 
.
The dart is thrown up in which case acceleration, g, acts downward in an opposite direction to its displacement, 
. Both collide after travelling for a time period, t. Let the height of the dart from the ground at collision be and the distance travelled by the ball measured from the top be .
It follows that 
.
Applying the equation of motion to each body (h = v_0t + 0.5at^2),
Ball:
(since 
.)
Dart:
(the acceleration is opposite to the displacement, hence the negative sign)
But
The height of the collision is the height of the dart above the ground, .
Answer:
A. How much matter an object has, plus the magnitude and direction of its motion
Explanation:
Momentum is defined as the product of mass by velocity, in the international system of measurements (SI) momentum has the following Units [kg*m/s].
P = m*v
where:
P = momentum Lineal [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Therefore the answer is A) How much matter an object has, plus the magnitude and direction of its motion
