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Tresset [83]
3 years ago
5

Which term describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface?

Physics
2 answers:
svet-max [94.6K]3 years ago
4 0

Answer: Option (D)

Explanation:

Unconformity refers to the surface that clearly demarcates the period of non-deposition. The rocks found below this are older and the rocks that are above this are the younger rocks. This unconformity is exposed to the surface due to the rapid erosion and slow accumulation of sediments.

The different types of unconformity are as follows-

  1. <u>Angular unconformity-</u> here, sedimentary rocks initially gets deposited, then it gets tilted due to tectonic activities and are eroded. Again new sedimentary rocks deposits forming an angle which is known as the angular unconformity.
  2. <u>Non-conformity-</u> here igneous rocks are intruded and undergoes erosion takes place. Then new sedimentary rocks are deposited and this of contact is known as the non-conformity.
  3. <u>Disconformity-</u> when some sequence of rocks are deposited, undergoes erosion and again new sequence of rocks gets deposited, which is known as disconformity.

Thus, the correct answer is option (D).

Lemur [1.5K]3 years ago
3 0

<em>The term that describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface is called</em> <em>unconformity.</em>

<em>Glad to help ya!! ;)</em>

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Answer:

The acceleration of the boxes is 1.5 ft/s²

The displacement of the boxes during the speed-up period is 0.1875 ft.

Explanation:

Hi there!

Let´s convert the 45 ft/min into ft/s:

45 ft/min ·  1 min/ 60 s = 0.75 ft/s

It takes the belt 0.5 s to reach this speed. Then, the acceleration of the boxes will be:

a = v/t

Where:

a = acceleration.

v = velocity.

t = time.

a = 0.75 ft/s / 0.5 s

a = 1.5 ft/s²

The acceleration of the boxes is 1.5 ft/s²

The equation of displacement is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the boxes at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

Since the origin of the frame of reference is located at the point where the boxes begin to move, x0 = 0. Since the boxes were initially at rest, v0 = 0. Then:

x = 1/2 · a · t²

x = 1/2 · 1.5 ft/s² · (0.5 s)²

x = 0. 1875 ft

The displacement of the boxes during the speed-up period is 0.1875 ft.

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3 years ago
A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
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Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

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at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

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