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Tresset [83]
3 years ago
5

Which term describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface?

Physics
2 answers:
svet-max [94.6K]3 years ago
4 0

Answer: Option (D)

Explanation:

Unconformity refers to the surface that clearly demarcates the period of non-deposition. The rocks found below this are older and the rocks that are above this are the younger rocks. This unconformity is exposed to the surface due to the rapid erosion and slow accumulation of sediments.

The different types of unconformity are as follows-

  1. <u>Angular unconformity-</u> here, sedimentary rocks initially gets deposited, then it gets tilted due to tectonic activities and are eroded. Again new sedimentary rocks deposits forming an angle which is known as the angular unconformity.
  2. <u>Non-conformity-</u> here igneous rocks are intruded and undergoes erosion takes place. Then new sedimentary rocks are deposited and this of contact is known as the non-conformity.
  3. <u>Disconformity-</u> when some sequence of rocks are deposited, undergoes erosion and again new sequence of rocks gets deposited, which is known as disconformity.

Thus, the correct answer is option (D).

Lemur [1.5K]3 years ago
3 0

<em>The term that describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface is called</em> <em>unconformity.</em>

<em>Glad to help ya!! ;)</em>

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ne true-breeding line of mice is obese and dark, and the other true-breeding line is lean and light. Dark is dominant to light,
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Answer:

 \frac{3}{8}

Explanation:

Let the allele for dark color be represented by "D" and the allele for light color be represented by "d"

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Genotype of true breeding dark and obese mice be DDOO

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DdOL

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DO DDOO DDOL DdOO DdOL

DL DDOL DDLL DdOL DdLL

dO DdOO DdOL ddOO ddOL

dL DdOL DdLL ddOL ddLL

dark and intermediate between obese and lean offspring genotype –  

2 DDOL, 4 DdOL  

So total six out of sixteen offspring are dark and intermediate between obese and lean -  

 \frac{6}{16} \\\frac{3}{8}

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