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2 years ago

Which term describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface?

Physics

2 answers:

svet-max [94.6K]2 years ago

4 0

Answer: Option (D)

Explanation:

Unconformity refers to the surface that clearly demarcates the period of non-deposition. The rocks found below this are older and the rocks that are above this are the younger rocks. This unconformity is exposed to the surface due to the rapid erosion and slow accumulation of sediments.

The different types of unconformity are as follows-

Angular unconformity- here, sedimentary rocks initially gets deposited, then it gets tilted due to tectonic activities and are eroded. Again new sedimentary rocks deposits forming an angle which is known as the angular unconformity.
Non-conformity- here igneous rocks are intruded and undergoes erosion takes place. Then new sedimentary rocks are deposited and this of contact is known as the non-conformity.
Disconformity- when some sequence of rocks are deposited, undergoes erosion and again new sequence of rocks gets deposited, which is known as disconformity.

Thus, the correct answer is option (D).

Lemur [1.5K]2 years ago

3 0

The term that describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface is called unconformity.

Glad to help ya!! ;)

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2 years ago

What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?

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A :-) for this question , we should apply
F = ma
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2 years ago

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

miss Akunina [59]

Answer:

0.07756 m

Explanation:

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We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by $v_{max}=A\omega$ where A is amplitude and $\omega$ is angular velocity

Angular velocity is given by $\omega=\sqrt{\frac{k}{m}}$ where k is spring constant and m is mass

So $v_{max}=A\sqrt{\frac{k}{m}}$

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k0ka [10]

Answer:

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In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

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