Explanation:
1) sin(37º)=x/10.3————>trigonometric ratio (sine)
2)7²+10²=c²—————-> pythagorean theorem
3) using sine—————> sin(51º)=9/x
using tangent —————> tan(51º)=9/x and x = 7.3 (rounded)
4)using pythagorean theorem————> 6²+7²=c²
angle b is tanx=6/7 where x = 40.6 degrees, angle a is tanx=7/6 where x = 49.4
Answers:
1)x= 6.2
2)x= 12.2
3)x= 11.6 (rounded)
4)x= 9.2
credit to <u>genan</u> for question 3 and 4
ur welcome :)
correct me if im wrong
brainliest please?
Let 
denote the value on the 
-th drawn ball. We want to find the expectation of 
, which by linearity of expectation is
![E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]](https://tex.z-dn.net/?f=E%5BS%5D%3DE%5Cleft%5B%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E5B_i%5Cright%5D%3D%5Csum_%7Bi%3D1%7D%5E5E%5BB_i%5D)
(which is true regardless of whether the 
are independent!)
At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.
and so
![E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5](https://tex.z-dn.net/?f=E%5BX_i%5D%3D%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E%7B10%7Dx%5C%2CP%28X_i%3Dx%29%3D%5Cfrac1%7B10%7D%5Cfrac%7B10%2810%2B1%29%7D2%3D5.5)
Then the expected value of the total is
![E[S]=5(5.5)=\boxed{27.5}](https://tex.z-dn.net/?f=E%5BS%5D%3D5%285.5%29%3D%5Cboxed%7B27.5%7D)
Answer:
the answer is -2x^9
Step-by-step explanation:
i know this because of photomath lolll
Answer:
The two parallel sides a and b are 17 cm and 23 cm respectively
Step-by-step explanation:
Area of a trapezium = {(a+b)/2} h
Where
h = height = 18 cm
a = parallel side 1 = x
b = parallel side 2 = x + 6
Area of a trapezium = {(a+b)/2} h
360 = {(x + x + 6) / 2} 18
360 = { (2x + 6) / 2} 18
360 = (2x + 6) 9
360 = 18x + 54
Subtract 54 from both sides
360 - 54 = 18x
306 = 18x
Divide both sides by 18
x = 306 / 18
= 17
x = 17 cm
a = parallel side 1 = x
x = 17 cm
b = parallel side 2 = x + 6
x + 6
= 17 + 6
= 23 cm
It went up 125% or 25 percent more
