Answer:
Quadrant IV, or the fourth quadrant.
Step-by-step explanation:
Plot your points, first plotting 5, then plotting -2.
F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320
Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640
Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280
Final Answer: -1280
Answer:
192
Step-by-step explanation:
12.5% is 24.
So 100% will be (100/12.5) x 24 = 192.
Done.
Answer:
The total distance traveled by the particle is S = 30.
Step-by-step explanation:
Given that velocity,
v(t) = 2t + 1
To find the total distance travel, we integrate the velocity function, v(t), to obtain the distance function s(t), and evaluate the resulting distance at the interval given. That is at t = 0 to t = 5.
Integrating v(t) with respect to t, we have
s(t) = t² + t + C.
At t = 5
s(5) = 5² + 5 + C
= 25 + 5 + C
= 30 + C
At t = 0
S(0) = 0 + 0 + C
= C
The required distance is now
S(5) - S(0)
= 30 + C - C
= 30.
