Answer:
Cobalt/Electron configuration
Explanation:
[Ar] 3d7 4s2
Answer:

-) Oxidizing agent: 
-) Reducing agent: 
Explanation:
The first step is separate the reaction into the <u>semireactions</u>:
A.
B.
If we want to balance in <u>basic medium </u>we have to follow the rules:
1. We adjust the oxygen with 
2. We adjust the H with 
3. We adjust the charge with 
Lets balance the first semireaction A. :

Now, lets balance semireaction B:

Finally, we have to add the two semireactions:
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Cancel out the species on both sides:

Simplifying the equation :

The
is <u>oxidized</u> therefefore is the <u>reducing agent</u>. The
is<u> reduced</u> therefore is the <u>oxidizing agent</u>.
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Answer:
The effective nuclear charge (often symbolized as Zeff or Z*) is the net positive charge experienced by an electron in a multi-electron atom. The term “effective” is used because the shielding effect of negatively charged electrons prevents higher orbital electrons from experiencing the full nuclear charge.
Explanation:
Answer:
0; +1; -1
Explanation:
The resonance structure of HN₃ is shown below (you can also use horizontal dashes to represent the bonding pairs).
The molecule has 16 valence electrons, and each N atom has an octet.
To get the formal charges, cut the covalent bonds in half.
Each atom gets the electrons on its side of the cut.
Formal charge = valence electrons in isolated atom - electrons on bonded atom
FC = VE - BE
(a) On Nₐ
VE = 5
BE = 1 lone pair (2)+ 3 bonding electrons = 2 + 3 = 5
FC = 5 - 5 = 0.
(b) On Nb:
VE = 5
BE = 4 bonding electrons = 4
FC = 5 - 4 = +1
(c) On Nc:
VE = 6
BE = 2 lone pairs(4) + 2 bonding electrons = 4 + 2 = 6
FC = 5 - 6 = -1